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Liula [17]
3 years ago
15

the base of a triangle exceeds the height by 5 yards. if the area is 187 square yards, find the length of the base and height of

the triangle?
Mathematics
1 answer:
alina1380 [7]3 years ago
4 0

We know that the base of the triangle is 5 yards more than the height of the triangle

Let base of the triangle be 'b' and height of the triangle be 'h'

⇒ b = h + 5

Also, we have been given that the area of the triangle is 187 square yards

We have to determine the length of the base and height of the triangle.

Area = \frac{1}{2} * b * h

⇒ Area = \frac{1}{2} * (h+5) * (h) = 187

⇒ \frac{1}{2} * (h+5) * (h)[/tex] = 187

⇒ \frac{h^{2}+5h}{2} = 187

⇒ h^{2}+5h = 187 * 2

⇒ h^{2}+5h - 374 = 0

⇒ h^{2}+22h -17h - 374 = 0

⇒ h (h+22) - 17 (h+22) = 0

⇒ (h-17) (h+22) = 0

⇒ h = 17 or h = -22

Since height can't be negative, so h = 17 yards

⇒ b = h + 5 = 17+5 = 22 yards

Hence, height of the triangle is 17 yards and the base is 22 yards.


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Consider strings of four decimal digits. Which rule must be used to find the number of strings of four decimal digits that have
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Answer:

36 possible ways

Step-by-step explanation:

Range of digit : 0 up to 9

To obtain the number of strings of 4 decimal digits that have exactly 3 digits that are 9s ; we use the multiplication rule :

In other to have exactly 3 digits from 4 that are 9s :

Say:

We have 3 9s and the last number could be any of the 10 possible digits except 9

First 9 = 1 possible way (since we have only one 9 between (0 to 9)

Second 9 = 1 possible way

Third 9 = 1 possible way

4th digit = 9 ways (could be any digit between 0 and 9, except 9)

Also, we consider the 4th digit's position ; as it could take up any of different positions in between the 9s = 4 ways

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1 * 1 * 1 * 9 * 4 = 36 possible ways

5 0
3 years ago
Suppose we wish to demonstrate that there is a difference between the proportions of wives and husbands who do laundry at home.
maxonik [38]

Answer:

Step-by-step explanation:

From this study:

The null hypothesis:

H_o : p_1 =p_2

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H_a : p_1 \ne p_2

This test is a two-tailed test.

However; we are told that the wives have 44 success out of 66, then the number of failures will be 22.

Then;

\hat p_1 = \dfrac{44}{66}

\hat p_1 = 0.6667

Similarly, the husbands have 18 success out of 46, then the number of failures will be 28

Then:

\hat p_2 = \dfrac{18}{46}

\hat p_2 = 0.3913

The pooled proportion p = \dfrac{18+44}{66+46}

p = \dfrac{62}{112}

p = 0.55357

The estimated standard error S.E is:

= \sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}

= \sqrt{ 0.55357(1-0.55357) \Big( \dfrac{1}{66} + \dfrac{1}{46} \Big)}

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The Z test statitics can now be computed as:

Z = \dfrac{ \hat p_1 - \hat p_2}{\sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}}

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p -alue = 0.004

Decision Rule:

Thus, at 0.01 significance level, we reject the null hypothesis because, p-value is less than that (i.e. significance level)

Conclusion:

We conclude that there is a significant  difference between the proportions.

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