Answer:
Step-by-step explanation:
Given that Of 450 college students, 110 are enrolled in math, 205 are enrolled in English, and 50 are enrolled in both. If a student is selected at random
the probability
(a) The student is enrolled in mathematics=
(b) The student is enrolled in English.=
(c) The student is enrolled in both.=
(d) The student is enrolled in mathematics or English.=
(e) The student is enrolled in English but not in mathematics.
=
(f) The student is not enrolled in English or is enrolled in mathematics.
=
1) When the denominator equals zero that is a critical point
=> x - 2 = 0 => x = 2.
So x = 2 is a critical point
2) Simplify the numerator to find an expresion of the king p(x) ≥ 0 or p(x) ≤ 0. Where p(x) equals zero you have other(s) critical point(s)
Multiply both terms:
[2x + 5] / [ x - 2] = [x - 1] / [x - 2]
for x ≠ 2 => 2x + 5 = x - 1
=> 2x - x = - 1 - 5
=> x = - 6
Then, the two critical points are x = 2 and x = - 6.
Answer: option B.
N P r = (n!)/((n-r)!)
8 P 4 = (8!)/((8-4)!)
8 P 4 = (8!)/(4!)
8 P 4 = (8*7*6*5*4!)/(4!)
8 P 4 = 8*7*6*5
8 P 4 = 1680
The final answer is 1680
=-30
-2*-3=6
-1*5=-5
6 x -5=-30
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