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Yakvenalex [24]
3 years ago
5

The apparent brightness of a star if it were viewed from a distance of 10 parsecs (32.6 light- years) is called ________.

Mathematics
1 answer:
Maru [420]3 years ago
8 0

Answer:

Absolute magnitude

Step-by-step explanation: Astronomy deals with the study of stars and other heavenly bodies. Astronomers use apparent magnitude to define how bright a star appears and shines from the earth.

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A fifth-degree polynomial equation with rational coefficients has the roots 3, 8i, and 7- radical 5. Which are also roots of the
Sliva [168]

Using <u>complex numbers and radicals</u>, it is found that the correct option is C.

When a complex number is a root of a polynomial function, it's conjugate also has to be.

  • Hence, since 8i is a root of the function, -8i is also a root.

The same is valid for radicals, as they are in the \pm format.

  • Since 7 - \sqrt{5} is a root, 7 + \sqrt{5} is also a root.

Hence, option C is correct.

For more on <u>complex numbers and radicals</u>, you can check brainly.com/question/25173944

8 0
2 years ago
Rita earns $10 per hour. She puts 5% of her earnings in savings. Write an inequality to find how many hours h Rita must work to
xz_007 [3.2K]
Find the percentage. 5 percent of 10 is 0.5. 50 cents.
25 X 2(AMOUNT OF 5 PERCENT OF A DOLLAR IN A DOLLAR) =  50.

50 hours
3 0
2 years ago
Read 2 more answers
Write two numbers that multiply to the value on the top and add to the value on bottom
Bas_tet [7]

Answer:

Step-by-step explanation:

-10 and 9

-10×9=-90

-10+9=-1

3 0
3 years ago
Could somebody please answer this?
jok3333 [9.3K]
Here are the resulting percentages:
LEAH = 3.5%
RATHA = 2.3%
ED = 1.8%
CHRIS = 4.2%
MARY = 2.5%

You arrive at this answer by dividing the bonus by the wages

BONUS/WAGE = PERCENTAGE OF BONUS TO WAGE.

Chris had the greatest percentage of wages in his bonus
3 0
3 years ago
PLEASE I NEED HELP! THANK YOU.
Elden [556K]

First set up a linear equation  and using the x and y values in the table see if it solves.

It doesn't solve so we know it isn't linear. ( I won't show all those steps because they aren't needed.)

Using the quadratic formula y = ax^2 +bx +c

Build a set of 3 equations from the table:

C is the Y intercept ( when X is 0), this is shown in the table as 6

Now we have y = ax^2 + bx + 6

-2.4 =4a-2b +6

1.4 = a-b +6

Rewrite the equations

a=b/2 -2.1

1.4 = b/2-2.1 +6

b = 5

a = 5/2 -2.1 = 0.4

replace the letters to get y = 0.4x^2 + 5x +6

4 0
3 years ago
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