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morpeh [17]
3 years ago
12

What is the kinetic energy of a 7.56 kg bowling ball that is rolling at a speed of 2 m/s ?

Physics
1 answer:
postnew [5]3 years ago
7 0

Answer:

K.E=?

Mass=7.56 kg

Velocity=2m/s

Solution::

K.E = 1/2mv^2

K.E=0.5*7.56*(2)^2

K.E= 0.5*7.56*4

K.E=15.12 joules.

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Answer:

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7 0
2 years ago
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I am struggling on this physics question. Brainly is my last hope. Could somebody please provide an answer to this question, wit
Aleks [24]

1) 29.4 N

The force of gravity between two objects is given by:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M and m are the masses of the two objects

r is the separation between the centres of mass of the two objects

In this problem, we have

M=5.97\cdot 10^{24} kg (mass of the Earth)

m=3.0 kg (mass of the box)

r=R=6.37\cdot 10^6 m (Earth's radius, which is also the distance between the centres of mass of the two objects, since the box is located at Earth's surface)

Substituting into the equation, we find F:

F=\frac{(6.67\cdot 10^{-11})(5.97\cdot 10^{24})(3.0)}{(6.37\cdot 10^6)^2}=29.4 N

2) g=9.8 m/s^2

Let's now calculate the ratio F/m. We have:

F = 29.4 N

m = 3.0 kg

Subsituting, we find

\frac{F}{m}=\frac{29.4}{3.0}=9.8 N/kg = 9.8 m/s^2

This is called acceleration of gravity, and it is the acceleration at which every object falls near the Earth's surface. It is indicated with the symbol g.

We can prove that this is the acceleration of the object: in fact, according to Newton's second law,

F=ma

where a is the acceleration of the object. Re-arranging,

a=\frac{F}{m}

which is exactly equal to the quantity we have calculated above.

5 0
3 years ago
____ have more energy than ____. A. Radio waves; microwaves B. Ultraviolet rays; X-Rays C. Gamma rays; infrared rays D. Radio wa
Aloiza [94]
C. Gamma rays have more energy than infrared rays
6 0
2 years ago
g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum decelerati
astraxan [27]

Given:

Initial speed of the motorcycle (u) = 35 m/s

Final speed of the motorcycle (v) = 0 m/s (Complete Stop)

Maximum deceleration of the motorcycle (a) = -1.2 m/s²

Required Equation:

\boxed{\bf{ v = u + at}}

Answer:

By substituting values in the equation, we get:

\rm \longrightarrow 0 = 35 + ( - 1.2)t \\  \\  \rm \longrightarrow  0 = 35 - 1.2t \\  \\  \rm  \longrightarrow 35 - 1.2t = 0 \\  \\  \rm  \longrightarrow 35- 35 - 1.2t = 0 - 35 \\  \\  \rm  \longrightarrow  - 1.2t =  - 35 \\  \\  \rm \longrightarrow  \dfrac{ - 1.2t}{ - 1.2}  =  \dfrac{ - 35}{ - 1.2}  \\  \\  \rm \longrightarrow  t = 29.167 \: s

\therefore Time taken by motorcycle to come to a complete stop (t) = 29.167 s

4 0
3 years ago
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