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2 years ago

What is the kinetic energy of a 7.56 kg bowling ball that is rolling at a speed of 2 m/s ?

Physics

1 answer:

postnew [5]2 years ago

7 0

Answer:

K.E=?

Mass=7.56 kg

Velocity=2m/s

Solution::

K.E = 1/2mv^2

K.E=0.5*7.56*(2)^2

K.E= 0.5*7.56*4

K.E=15.12 joules.

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If a boomerang is thrown 20 m in a straight line and returns exactly at the same spot from which it is thrown, what is its displ

Anettt [7]

Answer:

C) 0m

Explanation:

Since at the end of the day, it was not displaced

Displacement ti's a vector quantity

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2 years ago

What force must the worker exert to get the box moving & what force must the worker exert to accelerate the box at 0.1 meter

photoshop1234 [79]

Since static friction is the minimum force required to just start the motion of a stationary object.

Here if we need to start an object from rest then we required F = 700 N

So for the first part of the above problem Force will be F = 700 N

Now if the box is already moving then we will have to use kinetic friction force between box and floor

now we can write the equation of net force as

$F - F_k = m*a$

here

$F_k = kinetic friction = 220 N$

$m = mass = 500 kg$

$a = acceleration = 0.1 m/s^2$

now we will have

$F - 220 = 500* 0.1$

$F = 220 + 50 = 270 N$

3 0

2 years ago

A constant force of 5.00 N acts on a 2.50 kg object for 10.0 s. What are the changes in the object’s momentum and velocity?

dimulka [17.4K]

Hope this answer helps, cause Idk, I might be wrong, but I still, I used the correct formulas, so I might be correct

7 0

2 years ago

If you drive 30 miles in 40 minutes, and then 15 miles in 20 minutes, do you have a constant speed?

kompoz [17]

Answer:

A) yes

Explanation:

First section of trip: 30 miles in 40 minutes

Second section of trip: 15 miles in 20 minutes

The formula for speed is distance over time $k=\frac{d}{t}$

Calculate the speeds for each section of the trip.

First:

k = d/t

k = 30miles/40minutes <= reduce fraction by 10 (30÷10 and 40÷10)

k = 3 miles / 4 minutes

Second:

k = d/t

k = 15miles/20minutes <= reduce fraction by 5 (15÷5 and 20÷5)

k = 3 miles / 4 minutes

Therefore there is a constant speed because both sections of the trip are driving at "3 miles / 4 minutes".

3 miles / 4 minutes can be also formatted as:

0.75 miles per minute.

7 0

2 years ago

This problem uses the same concepts as Multiple-Concept, except that kinetic, rather than static, friction is involved. A crate

Bingel [31]

Answer:

1.96 m/s^2

Explanation:

angle of inclination, θ = 30.6°

coefficient of friction, μ = 0.36

Acceleration of the crate

a = g Sin θ - μ g Cos θ

a = 9.8 ( Sin 30.6 - 0.36 x Cos 30.6)

a = 9.8 ( 0.509 - 0.309)

a = 1.96 m/s^2

Thus, the acceleration f the crate is 1.96 m/s^2.

3 0

2 years ago