3 years ago

What is the kinetic energy of a 7.56 kg bowling ball that is rolling at a speed of 2 m/s ?

Physics

1 answer:

postnew [5]3 years ago

7 0

Answer:

K.E=?

Mass=7.56 kg

Velocity=2m/s

Solution::

K.E = 1/2mv^2

K.E=0.5*7.56*(2)^2

K.E= 0.5*7.56*4

K.E=15.12 joules.

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Explanation:

Given

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$v_y=u+at$

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Range is given by

R=ut

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$68=u\times t$

$t=\frac{68}{u}$

substitute the value of t in eqn 1

$v_y=9.81\times \frac{68}{u}$

$v_y\times u=9.81\times 68=667.08$ --------2

and $tan(3)=\frac{v_y}{u}$

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3 years ago

If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure

anyanavicka [17]

<h3>Answer:</h3>

p=300 Pa

<h3>Explanation:</h3>

_______________

S=3 m²

F=900 N

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1 year ago

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serg [7]

Answer: So finally, the dimensional formula of the radius of gyration will be written as: [M0LT0]. The power of zero on the dimension of the mass and time shows that the mass and the time dimensions are zero for the radius of gyration. Hope this helps (:

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Answer:

0.00129rad/s

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w = v/r

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w = 8940.8/6,920,162

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Hence the angular velocity generated is 0.00129rad/s

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