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SSSSS [86.1K]
3 years ago
7

A ball of mass 24.1 g is attached to a cord of length 0.417 m and rotates in a vertical circle. What is the minimum speed the ba

ll must have at the top of the circle so the cord does not become slack? The acceleration of gravity is 9.8 m/s².
Answer in units of m/s.
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

<em>the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

<em></em>

Explanation:

In order to avoid slack, the centripetal force of the ball must equal its weight at the top of the circle. Therefore,

F_c = F_g

m v² / r = m g

v² = g r

v = √[g r]

v = √[(9.8 m/s²)(0.417 m)]

<em>v = 2.02 m/s </em>

Therefore,<em> the minimum speed that the ball must have so that the cord does not become slack is</em> <em>2.02 m/s.</em>

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