What is 4+1+20+100=1000

I neeed the answer plssss

Maru [420]

Answer:

300km

Step-by-step explanation:

if 1 hr=80

then take 80 and multiply it by 3.75

hope this helps!

please give brainiest if you want<3

6 0

2 years ago

Read 2 more answers

Erythromycin is a drug that has been proposed to possibly lower the risk of premature delivery. A related area of interest is it

katrin2010 [14]

Answer:

$z=\frac{0.333 -0.3}{\sqrt{\frac{0.3(1-0.3)}{195}}}=1.01$

$p_v =P(z>1.01)=0.156$

So the p value obtained was a very low value and using the significance level asumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of women who complain of nausea between the 24th and 28th week of pregnancy is not significantly higher than 0.3 or 30%

Step-by-step explanation:

Data given and notation

n=195 represent the random sample taken

X=65 represent the women who complain of nausea between the 24th and 28th week of pregnancy

$\hat p=\frac{65}{195}=0.333$ estimated proportion of women who complain of nausea between the 24th and 28th week of pregnancy

$p_o=0.3$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.3.:

Null hypothesis: $p\leq 0.3$

Alternative hypothesis: $p > 0.3$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.333 -0.3}{\sqrt{\frac{0.3(1-0.3)}{195}}}=1.01$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed is $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>1.01)=0.156$

So the p value obtained was a very low value and using the significance level asumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of women who complain of nausea between the 24th and 28th week of pregnancy is not significantly higher than 0.3 or 30%

6 0

3 years ago

Given the linear correlation coefficient r and the sample size n, determine the critical values of r and use your finding to sta

Dafna11 [192]

Answer: r represents a significant linear correlation.

Step-by-step explanation:

GIven : Linear correlation coefficient: r = 0.543

Sample size: n= 25

Significance levle: $\alpha=0.05$

Degree of freedom : n-2 = 25-2=23

Now, we check r critical value table for value with df = 23 and $\alpha=0.05$ .

Critical value = ±0.396 [From r critical value table]

Since r = 0.543 > 0.396, that means there is significant linear correlation.

Hence, r represents a significant linear correlation.

8 0

3 years ago

On a word processing test, Iko typed 694 words in 15 minutes. On that same test six days later, Iko typed 753 words in 15 minute

Misha Larkins [42]

Answer:

The improve in speed is 3.9334 words/min

Step-by-step explanation:

we will find speed at both occasions and then we can subtract them

First test:

total number of word =694

total time =15 min

we know that

speed = (total number of words)/( total time)

now, we can plug values

speed is

$=\frac{694}{15}$ word/min

$s_1=46.2666$ word/min

Second test:

total number of word =753

total time =15 min

we know that

speed = (total number of words)/( total time)

now, we can plug values

speed is

$=\frac{753}{15}$ word/min

$s_2=50.2$ word/min

So, improve in speed is

$=s_2-s_1$

$=50.2-46.2666$

$=3.9334$ word/min

7 0

2 years ago

Solve 12x + 6 2 9x + 12. A. X2 B. xs2 O C. X26 0 D. Xs6 SUBNANT

Alexxx [7]

Answer:

269

Step-by-step explanation:

Solve 12x + 6 2 9x + 12.

A. X2

B. xs2

O

C. X26

0

D. Xs6

8 0

2 years ago