I would go with option C. x, in the first equation.
The X term has a coefficient of 3, the lowest common factor amongst the 3 terms making for easy isolation of the variable.
Answer: i guess the problem is with P(x) => "x = 
", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and 
= 0. So p(0) is true.
b) x = 1 and 
= 1, so P(1) is true.
c) x = 2, and 
= 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and = 1, and 1 ≠ -1, so P(-1) is false.
Answer:
D) f(x) = 6x
Step-by-step explanation:
Answer: 1 3/4 is your mixed fraction and 7/4 is the improper fraction.
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.
Expanding, we get
(x³-3x+1)² = (x³-3x+1)(x³-3x+1)
= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1
= x^6 - 6x^4 + 2x³ +9x²-6x + 1
In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots
