The probability that a randomly selected score is greater than 334 will be 0.02275.
<h3>What is a normal distribution?</h3>
The Gaussian Distribution is another name for it. The most significant continuous probability distribution is this one. Because the curve resembles a bell, it is also known as a bell curve.
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The GRE is an entrance exam that many students are required to take in order to apply to graduate school. In 2014, the combined scores for the Verbal and Quantitative sections were approximately normally distributed with a mean of 310 and a standard deviation of 12.
Then the probability that a randomly selected score is greater than 334 will be
The z-score is given as
z = (x - μ)/σ
z = (334 - 310)/12
z = 24/12
z = 2
Then the probability will be
P(x > 334) = P(z > 2)
P(x > 334) = 1 - P(x<334)
P(x > 334) = 1 - 0.97725
P(x > 334) = 0.02275
More about the normal distribution link is given below.
brainly.com/question/12421652
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For this problem, we are going to use the <em>law of sines</em>, which states:
In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, 
. Then, we can find the third side. Using the law of sines, we can find:
We can use this to solve for :
Now, we can find 
:
Using this, we can find 
:
c is approximately 17.5.
Answer:
6 containers
6 ounces of fruit snack will be left over
Step-by-step explanation:
1 pound = 16 ounces
⇒ ¹/₂ pound = 8 ounces
Total weight = weight of dried apples + weight of dried cranberries
= 36 + 18
= 54 ounces
Containers needed = total weight ÷ weight of snacks in one container
= 54 ÷ 8
= 6.75
Therefore, he will fill 6 containers
Snack left over = total weight - (number of containers × weight of snacks one container will hold)
= 54 - (6 × 8)
= 54 - 48
= 6 ounces
