2+2=======================

Sav [38]

Answer:

Option 3

Step-by-step explanation:

Using the order of operations, you will find out that 7 x 10^3 = 7,000, and 3 x 10^2 = 300. Dividing 7,000 by 300 will get you 23.333~, so 300 does go into 7,000 a little more than 20 times.

8 0

2 years ago

3 + (10 − 2)2 ÷ 4 ⋅ 1/2 whole to the power of 4

pshichka [43]

Answer:

equals 4 i believe..

Step-by-step explanation:

4 0

3 years ago

Why is dividing a fraction by 3 and then multiplying by 2 the same as multiplying by 2/3?

Tema [17]

It would be the same you would already be dividing by 3 because it’s the denominator and the numerator is 2

7 0

2 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

Help Please?

Gemiola [76]

Answer:

1 a = 70%

b 6.5 times

c green = 16%

2. ????? Very poorly worded question

2. a 54%

b. 46%

c. 70%

d. 27%

Step-by-step explanation:

1. Students in a class were asked to tell their favorite color.

a. What percent said red, blue, or yellow? __% said red, blue, or yellow.

red is .26

blue is .40

yellow is .04

---------------------

.70 = 70 %

b. How many times more students said red than yellow?

red .26

yellow is .04

.26/.04 = 6.5 times

c. What percent of students said green? __% said green.

The circle must total 100 %

Red + blue + yellow + purple + green = 100

26+ 40 + 4 + 14 + green = 100

84 + green = 100

Subtract 84 from each side

84-84 + green = 100-84

green = 16

2. Which two methods could be used to find the percent of students who said green?

We can either convert the percents to decimals or the decimals to percents

The total percents must equal 100%

The total decimal must equal 1

a. Find the sum of the percents given in the circle graph.

If they only want the ones written on the graph as percents

(14+40) = 54%

b. Find the sum of the percent forms of the numbers given in the circle graph. Subtract the result from 100%.

100 - 54% = 46%

c. Find the sum of the decimal forms of the numbers given in the circle graph. Subtract that sum from 1. Change the result to a percent.

.26+.04 = .3

1-.3 = .7

70%

d. Find the sum of half of the percents given in the circle graph. Subtract that total from 50%.

1/2 (46%) = 23%

50 -23 = 27%

5 0

3 years ago