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3 years ago

12n^2+48n = -n^3-64 factoring polynomial equations

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Answer:

Step-by-step explanation:

12n2+48n=−n3−64

Step 1: Subtract -n^3-64 from both sides.

12n2+48n−(−n3−64)=−n3−64−(−n3−64)

n3+12n2+48n+64=0

Step 2: Factor left side of equation.

(n+4)(n+4)(n+4)=0

Step 3: Set factors equal to 0.

n+4=0

n=−4

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What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16 y = –4 y = –2 y = 4 y = 6

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PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the numerator:

$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the denominator:

$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

Simplify:

$4x^{3}$

-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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