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2 years ago

15

Two Friends have agreed to do a job with pace $2,000 total together there receive apart payment Of 0.25 Of the total amount How

much of part payment should reach friend receive ,if they split it equally?
A.$250
B.500
C.$1000
D.1500

1 answer:

o-na [289]2 years ago

7 0

Well if they’re getting a quarter of it, they’re receiving 500, 500 divided by 2 is 250 so I would guess A

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《MATHEMATICS》

Law Incorporation [45]

<h2>Hey,there..</h2>

${3}^{2} - {2}^{2} \\ (3 + 2) \times (3 - 2) \\ 5 - 1 \\ = 4$

$2) \frac{1}{2} + \frac{2}{3} \\$

$\frac{3+2}{6} \\$

$\frac{5}{6}$

<h2>Hope it helps...</h2>

5 0

2 years ago

Read 2 more answers

What is the linear function of f-10)=12 and f(16)=-1

Natali5045456 [20]

<span>f(-10)=12, x = -10, y = 12

f(16)=-1, x = 16, y = -1.

so, we have two points, let's check with that,

</span> $\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -10 &,& 12~) 
% (c,d)
&&(~ 16 &,& -1~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-12}{16-(-10)}\implies \cfrac{-1-12}{16+10}
\\\\\\
\cfrac{-13}{26}\implies -\cfrac{1}{2}$
<span>
</span> $\bf \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)} y-12=-\cfrac{1}{2}[x-(-10)]
\\\\\\
y-12=-\cfrac{1}{2}(x+10)\implies y-12=-\cfrac{1}{2}x-5\implies y=-\cfrac{1}{2}x+7$ <span>
</span>

3 0

3 years ago

(1 point) The distribution of actual weights of 8-oz chocolate bars produced by a certain machine is normal with mean 7.8 ounces

Svet_ta [14]

Answer:

Probability that the average weight of a bar in a Simple Random Sample (SRS) with five of these chocolate bars is between 7.64 and 7.9 ounces is 0.9235.

Step-by-step explanation:

We are given that the distribution of actual weights of 8-oz chocolate bars produced by a certain machine is normal with mean 7.8 ounces and standard deviation 0.15 ounces.

A simple random sample of five of these chocolate bars is taken.

<em>Let </em> $\bar X$ <em> = sample average weight of a bar</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = average weight = 7.8 ounces

$\sigma$ = standard deviation = 0.15 ounces

n = sample of chocolate bars = 5

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the the average weight of a bar in a Simple Random Sample (SRS) with five of these chocolate bars is between 7.64 and 7.9 ounces is given by = P(7.64 ounces < $\bar X$ < 7.90 ounces)

P(7.64 ounces < $\bar X$ < 7.90 ounces) = P( $\bar X$ < 7.90) - P( $\bar X$ $\leq$ 7.64)

P( $\bar X$ < 7.90) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 7.90-7.80}{{\frac{0.15}{\sqrt{5} } }} }$ ) = P(Z < 1.49) = 0.93189 {using z table}

P( $\bar X$ $\leq$ 7.64) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 7.64-7.80}{{\frac{0.15}{\sqrt{5} } }} }$ ) = P(Z $\leq$ -2.39) = 1 - P(Z < 2.39)

= 1 - 0.99158 = 0.00842

<em>The above probability is calculated by looking at the value of x = 2.39 and x = 1.49 in the z table which has an area of 0.99158 and 0.93189 respectively.</em>

Therefore, P(7.64 ounces < $\bar X$ < 7.90 ounces) = 0.93189 - 0.00842 = 0.9235.

8 0

3 years ago

How do I get "P" by itself?

OleMash [197]

A/(1+rt)=P

this step should be the least of your concerns though

7 0

3 years ago

Read 2 more answers

The denominator of a fraction in its simplest form is greater than the numerator by 5 . If 3 is added to the numerator, and 2 ad

TiliK225 [7]

Answer:

The original fraction is 1/6

Step-by-step explanation:

Here we have a word problem as follows

Let the Denominator be D and

The Numerator be N

D = 5 + N

$\frac{N+3}{D+2} = \frac{N}{D} +\frac{1}{3}$

Therefore,

$\frac{N+3}{N+5+2} = \frac{N}{N+5} +\frac{1}{3}\Rightarrow \frac{N+3}{N+7} = \frac{N}{N+5} +\frac{1}{3}$

Which gives

$\frac{N+3}{N+7} - \frac{N}{N+5} =\frac{1}{3}$ and then we have

$\frac{N+15}{N^2+12\cdot N+35} = \frac{1}{3}$

Therefore, we have

$3\cdot N+45 ={N^2+12\cdot N+35}{$ and

$N^2 +9\cdot N-10 =0$

Which gives

$(N-1)\cdot (N+10) = 0$

That is the numerator = 1 or -10

and the denominator = N + 5 is therefore,

1 + 5 = 6 or

-10 + 5 = -5

The original fraction is therefore

$\frac{1}{6} \hspace {0.2 cm}$

3 0

3 years ago

Read 2 more answers