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Rudiy27
3 years ago
9

A square with a side length of x+6 has the same perimeter as an equilateral triangle with a side length of 4 x what is the area

of the square
Mathematics
1 answer:
prohojiy [21]3 years ago
7 0
The perimeter of the equilateral triangle is 3s and s=4x so the perimeter is:

12x

And we are told that the perimeter of the square is the same.  And that perimeter is 4s where s=(x+6) so that perimeter is equal to

4x+24, and again, we are told that these two values are equal so we can solve for x...

12x=4x+24

8x=24

x=3 and if x=3 then the side length is (x+6)=9

So the area of the square is always A=s^2 and s=9 thus:

A=9^2

A=81 u^2
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Step-by-step explanation:

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19. Given that angle BFC = 58°. Angle BXG = 48° and angle CBF 22 Find () 2BGX (iv) BCG (i) 2BGF (iv) ZBFG (ii) BCF H EE 58 48° D
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The unknown angles in the cyclic quadrilateral is as follows:

∠BGX = 74° (sum of angles in a triangle)

∠BGF = 180° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 100°(sum of angles in a triangle)

∠BCG  = 26°

∠BFG = 22°

<h3>Cyclic Quadrilateral</h3>

A cyclic quadrilateral has all its angles equal to 360 degrees. The sum of angles in a cyclic quadrilateral is equals to 360 degrees.

Let's find the missing angles as follows:

∠BGX = 180 - 48 - 58 = 74° (sum of angles in a triangle)

∠BGF = 180 - 100 = 80° (opposite angles of cyclic quadrilateral are supplementary)

∠BCF = 180 - 22 - 58 = 100°(sum of angles in a triangle)

∠BCG = 100 - 74 = 26°

∠BFG ≅ CBF = 22°(alternate angles)

learn more on angles here: brainly.com/question/19430381

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