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horrorfan [7]
3 years ago
5

A person in a casino decides to play 3 games of blackjack. let w denote a win and l denote a loss. define the event a as "the pe

rson wins at least one game of blackjack". what are the possible outcomes for this event?
Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer: The answer is {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.



Step-by-step explanation: Given that a person in the casino is going to play 3 games of blackjack. Here, 'w' denotes a win and 'l' denotes a loss.  

Also, let 'A' be the event that the person wins at least one game of blackjack. Then, the outcomes of Event 'A' are

(i) win in 1st game     loss in 2nd game       loss in 3rd game

(ii) win in 1st game     win in 2nd game        loss in 3rd game

(iii) win in 1st game     loss in 2nd game       win in 3rd game

(iv) win in 1st game     win in 2nd game        win in 3rd game

(v) loss in 1st game     loss in 2nd game       win in 3rd game

(vi) loss in 1st game     win in 2nd game        loss in 3rd game

(vii) loss in 1st game     win in 2nd game       win in 3rd game

Thus, the outcomes of the event A are (w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l) and (l, w, w).

Thus, A = {(w, l, l), (w, w, l), (w, l, w), (w, w, w), (l, l, w), (l, w, l), (l, w, w)}.


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tresset_1 [31]

The average rate of change of <em>g(x)</em> over the interval [2, 8] is given by

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2)

In other words, it's the slope of the line through the points (2, <em>g</em> (2)) and (8, <em>g</em> (8)).

Use the definition of the function to evaluate it at the points in the numerator:

• 8 ≥ 4, so using the second piece, <em>g</em> (8) = -0.5(8) + 8 = 4

• 2 < 4, so <em>g</em> (2) = 5(2) + 1 = 11

Then the average rate of change is

(<em>g</em> (8) - <em>g</em> (2)) / (8 - 2) = (4 - 11) / 6 = -7/6

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3 years ago
180 = −9d + 9 d = I need to find what d is
omeli [17]

Answer:

-19

Step-by-step explanation:

3 0
3 years ago
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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference​
allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}

so that

a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d

a_n=a_1+(n-1)d

33=8+(n-1)d

21=(n-1)d

n has to be an integer, which means there are 4 possible cases.

Case 1: n-1=1 and d=21. But

\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123

Case 2: n-1=21 and d=1. But

\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123

Case 3: n-1=3 and d=7. But

\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123

Case 4: n-1=7 and d=3. But

\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123

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3 years ago
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Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: y = 3 \cos(10 (x -\pi))

We can assume the parent function to be:

y = \cos (x)

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y = A*\cos((\frac{2\pi}{B})(x-c))

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

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A = 3

c = \pi

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Solve for B

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Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

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5 0
3 years ago
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