It is true that the product of two consecutive even integers are always one less than the square of their average.
<u>Step-by-step explanation</u>:
Let the two consecutive odd integers be 1 and 3.
- The product of 1 and 3 is (1
3)=3 - The average of 1 and 3 is (1+3)/2 =4/2 = 2
- The square of their average is (2)² = 4
∴ The product 3 is one less than the square of their average 4.
Let the two consecutive even integers be 2 and 4.
- The product of 2 and 4 is (24)=8
- The average of 2 and 4 is (2+4)/2 =6/2 = 3
- The square of their average is (3)² = 9
∴ The product 8 is one less than the square of their average 9.
Thus, It is true that the product of two consecutive even integers are always one less than the square of their average.
Answer:
<u> 105</u> students could prefer kiwi if there are 357 total students.
Step-by-step explanation:
Given:
The ratio of students who prefer pineapple to students who prefer kiwi is 12 to 5.
Now, to find number of students prefer kiwi if there are 357 total students.
Let the students prefer pineapple be 
And the students prefer kiwi be 
Total students = 357.
So, we set an equation to get the number of students who prefer kiwi.
According to question:
<em>Dividing both sides by 17 we get:</em>
<em>Thus, students prefer kiwi are:</em>
Therefore, 105 students could prefer kiwi if there are 357 total students.
If 9 is the radius and 20 is the height then it would be 5089.4 cm^3
Answer:
Step-by-step explanation:
LET ORANGES=X
PEARS ARE 3 TIMES =3X
LET CHILDREN=Y
IF WE GIVE 5 ORANGES PER CHILD WE NEED 5Y ORANGES.SO THIS =X
X=5Y........................I
IF WE GIVE 8 PEARS PER CHILD WE NEED 8Y PERARS...THERE ARE STILL 21 PEARS LEFT OUT AFTER THIS THAT IS
8Y+21=3X....................II
SUBSTITUTING FOR X FROM EQN.I..
8Y+21=3*5Y
15Y-8Y=21
7Y=21
Y=3
X==5Y=5*3=15..
SO CHILDREN =3
ORANGES=15
PEARS=3*15=45
THANKYOU AND PLEASE AMRK IT BRAINLIEST
