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Yanka [14]
2 years ago
10

What is the equation of the line that passes through the point (5, 1) and has a slope of 1?

Mathematics
1 answer:
Savatey [412]2 years ago
8 0

Answer:

y=fkef

Step-by-step explanation:

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Please answer the following
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Answer:

cot∅ = (-2√30)/7.

Step-by-step explanation:

Given the value of csc∅ = -13/7 and ∅ is in quad III.

We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).

It means y = -7, r = 13.

We know x² + y² = r².

x² = r² - y²

x² = (13)² - (-7)² = 169 - 49 = 120.

x = √120 = 2√30.

we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.

Hence, cot∅ = (-2√30)/7.

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