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sergejj [24]
3 years ago
11

Twice the number v + 1Answer:​

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

2(c+1)

=

2c+2

Step-by-step explanation:

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1 Solve for the unknown variable:
Burka [1]

Answer:

Approximately 6.4

Step-by-step explanation:

We can use the pythagorean thereom here, that tells us (a^2)+(b^2)=c^2. C is the hypotenuse, the side opposite from the right angle, while a and b are the other sides. We can insert 5 and 4 as a and b, and solve for c

:(5^2)+(4^2)=c^2

:25+16=c^2

:41=c^2

:sqrt(41)=6.4=c              (We square rooted both sides. 6.4 is only rounded to the nearest hundredths place.) Hope this helps!

8 0
2 years ago
Read 2 more answers
Julian scored 45 points in a video game. Brenden scored 3 times as many points. How many points did Brenden score?
Zepler [3.9K]
45 times 3 = 135

135 is the answer.
3 0
3 years ago
fie abc un triunghi cu masura unghiului a de 90 de grade ab este 6 cm bc=10 si ca=8 calculati;sin b; tg b; sin c; tg c; cos b; c
lions [1.4K]
SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
sinC = cosB = AB/ BC = 6/10 = 3/5;
tgC = ctgB = AB/ AC = 6/8 = 3/4.

6 0
3 years ago
The diameter of a round dinner plate is 10 inches. What's the area of the plate?
topjm [15]
A= pi times r*r so if you are using 3.14 as pi the answer is 78.5 because 5x5=25
25x3.14=78.5
5 0
3 years ago
Is it possible for a number to be a rational number that is not an interger but is a whole number. Explain
mylen [45]

Whole numbers are a subset of integers, which in turn are a subset of rational numbers.

So, every whole number is an integer, and every integer is a rational number.

So, it is possible for a rational number not to be an integer. Think of any decimal number: 1.356 is a rational number, but it's not an integer.

On the other hand, if a number is not an integer, it can't be a whole number, because all whole numbers are integers.

5 0
3 years ago
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