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maria [59]
3 years ago
9

Please Solve this answer 9c+4=-23

Mathematics
2 answers:
valina [46]3 years ago
8 0

9c=-23-4

9c=-27

c=-3 the answer is -3

poizon [28]3 years ago
6 0
-2.1111111111111111111111111111111111111111111111
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zhuklara [117]
The answer is the first one
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Levart [38]

Answer:

(-1)+(-3)=-4

Step-by-step explanation:

We were originally on -1.

But we jumped to -4.

-4 is 3 spaces to the left of -1.

In other words, we subtract 3 into -1.

Another way of saying this is that we added -3 to -1.

Therefore, our equation is:

(-1)+(-3)=-4

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3 years ago
Write the expression n-4 using a positive exponent. Leave answer in EXPONENTIAL NOTATION OR EXPONENTIAL FORM. PLEASE HELP ME I D
Nitella [24]

Answer:

1/ n^4

Step-by-step explanation:

n^-4

We know that a negative exponent in the numerator moves it to the denomintor

a^-b = 1/a^b

n^-4 = 1/ n^4

6 0
3 years ago
A taco shop is offering a 20% discount on their nacho plate. The original cost of the nacho plate is $15. After applying the dis
Serga [27]

Answer:

3$

Step-by-step explanation:

To find percentage on a discount like this all you have to do is multiply the pre-discount number by your discount percentage.

So all you have to do is:

15 x 0.20

which gives you an answer of 3.

Thus the post-discount amount is $3.

8 0
3 years ago
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
sattari [20]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

8 0
3 years ago
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