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Andrew [12]
3 years ago
10

321 ÷ 40 long division what the answer showing work

Mathematics
2 answers:
vodomira [7]3 years ago
7 0
40 goes into 32 0 times 40 goes into 321 8 times 40 times 8 equls 320 so 8r1
blagie [28]3 years ago
5 0
\large \begin{array}{cc} \begin{array}{lllll} ~~\,\,321~~~~&|\!\!\!\!\!&\underline{~~40\qquad\qquad}\\ -\underline{\,320}&\!\!\!\!\!&~~8\\ ~~~~~~1&\!\!\!\!\!& \end{array}&\begin{array}{c} 8\times 40=320 \end{array} \end{array}


\large \\\begin{array}{l} \textsf{When you divide }321\textsf{ by }40\\\\ \bullet~~\textsf{the quotient is }8;\\\\ \bullet~~\textsf{the remainder is }1.\\\\\\\\ \boxed{\begin{array}{ccccccc} 321&\!\!\!=\!\!\!\!\!\!\!\!\!&\mathbf{8}&\!\!\!\!\!\!\!\times&40&\!+\!\!\!\!\!\!\!\!\!\!&\mathbf{1}\\\\ &&\downarrow&&&&\downarrow\\\\ &&\text{quotient}&&&&\text{remainder} \end{array}} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2182397


I hope this helps. :-)


Tags: <em>long division integer quotient remainder</em>

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Reptile [31]

Answer: Hello!

first let's note the things we already know:

there is a 16- lap race and the oval has one mile of length, then each of the laps has a length of one mile, and the whole race has 16 miles in total

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then we could write the Bobby equation as B(t) = 6 miles + 94mph*t

where t represents the time in hours.

now we could see how much time Bobby needs to end the race:

B(x) = 6mi + 94mph*x = 16mi

94mph*x = 16mi - 6mi = 10mi

x = (10/94)h = 0.106h

so Bobby needs 0.106 hours to finish the race, and we want to know which velocity Rick should have in order to reach the end of the race at the same time as Bobby.

Rick is starting the race, so he needs to do 16 miles in 0.106 hours, and as we know velocity is distance over time; so the average velocity of Rick is:

V = 16mi/0.106h = 150.9mph

Now let's see the hint:

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3 years ago
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BARSIC [14]

Answer:

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Step-by-step explanation:

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<h3 /><h3>What will be the mean?</h3>

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Thus the set of data 6, 2, 2, 2  will have the least dispersion from their mean.

<h3 />

To know more about mean follow

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