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Vsevolod [243]
2 years ago
11

A photograph has an area of 50 square inches and a perimeter of 30 inches. What are the dimensions of the photograph

Mathematics
1 answer:
Mashcka [7]2 years ago
4 0

Answer: The dimensions are that 2 sides are 5 inches and two are 10 inches.

Step-by-step explanation:

The are is 50 so the dimensions should equal 50 when you do height times width. So 5*10=50 and 5+5+10+10=30

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Answer:

6:5

Step-by-step explanation:

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2 years ago
-10.23<br> _______<br> -2.3. How to solve?
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If their food and beverages costs$25.30 and there is an 8% meals tax, how much is the bill
Mashutka [201]
Hey there Unrazed90,

Answer : 

100% = $25.30
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8 0
3 years ago
Which postulates are used to find the perimeter of a shape?
Illusion [34]

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5 0
3 years ago
Someone please help me on this I'm unsure if my answer is correct
mafiozo [28]

Answer:

A. length = 23 cm; width = 5 cm

Step-by-step explanation:

So if 4 times the width would be 4w and 3 more than would be + 3, the equation would be l = 4w + 3. If the perimeter is 56, then the new equation, 2(4w + 3) + 2(w) = 56 can be formed. This simplifies to 8w + 6 + 2w = 56, then to 10w + 6 = 56, then to 10w = 50, and finally, w = 5. So the width is 5, and now plug it into the first equation.

l = 4(5) + 3, becomes l = 20 + 3, becomes l = 23.

So the dimensions are: length = 23 cm, width = 5 cm.

*And just to be sure, 2(23 + 5) = 2(28) = 56 which is correct.

4 0
2 years ago
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