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3 years ago

3.8 times 10-8 to standard notation

1 answer:

8 0

Standard notation is when the number is fully written. If your question is 3.8 times 10 to the negative 8th, then the answer is 0.000000038. If your question is 3.8 times 10 the positive 8th, then the answer is 380,000,000.

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Whats is 3/5 as a percent

likoan [24]

60%; Since 1/5 is .2 or 20% and then multiply that by 3.

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3 years ago

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Does anyone know this ?

Sedbober [7]

which # do you whant the answer to

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3 years ago

Describe the relationship between the values of the digits of 9,999,999

Rina8888 [55]

They're all divisible by 9 and 3. They're all equal to each other.

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3 years ago

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Use the iterative rule to find the 11th term in the sequence.

dolphi86 [110]

Answer:

-4

Step-by-step explanation:

The general, nth term, of a sequence is given by the formula:

$a_n=18-2n$

We can plug in n = 1 to find the first term, thus we have:

$a_1=18-2(1)\\a_1=16$

We can plug in n = 2, to the find the 2nd term, which is:

$a_2=18-2(2)\\a_2=14$

Similarly, to get 11th term, we simply plug in n = 11 into the general term rule. so we have:

$a_n=18-2n\\a_{11}=18-2(11)\\a_{11}=18-22\\a_{11}=-4$

11th term is -4

3 0

3 years ago

The hypotenuse of a right triangle is 24 ft. long. the length of one leg is 44 ft. more than the other. find the lengths of the

Mekhanik [1.2K]

The way to solve the missing side of a right triangle is normally by the Pythagorean Theorem:
${a}^{2} + {b}^{2} = {c}^{2} \\ {a}^{2} = {c}^{2} - {b}^{2} \: \infty \: \sqrt{ {a}^{2} } = \sqrt{( {c}^{2} - {b}^{2}) } \\ a= \sqrt{( {c}^{2} - {b}^{2}) }$
where c always is the hypotenuse
So c = 24 ft
b = 44 + a
${a}^{2} + {b}^{2} = {c}^{2} \\ {a}^{2} + {(a + 44)}^{2} = {24}^{2} \\ {a}^{2} + {a}^{2} + 88a + 1936 = 576$
Now combine like terms:
$2{a}^{2} + 88a + 1936 = 576 \\ 2{a}^{2} + 88a + 1936 - 576 = 0 \\ 2{a}^{2} + 88a + 1360 = 0$
Now we have to try to factor this quadratic equation, first let's take out 2:
$2({a}^{2} + 44a + 680) = 0$
we need factors of 680 whose sum = 44
20×34, 10×68, 17×40
however... 20+34=54, 10+68=78, 17+40=57
So we will need to use the quadratic equation unfortunately :(
$x = ( - b + - \sqrt{( {b}^{2} - 4ac)}) \div 2a$
Now the "x" is actually our "a", the a is 1, b is 44, c is 680
$a = ( - 44 + - \sqrt{( {44}^{2} - 4(1)680)}) \\ \div \: 2(1) \\ a = ( - b + - \sqrt{(1936 - 2720)}) \\ \div \: 2$
$a = ( - 44 + - \sqrt{(-784)}) \\ \div \: 2 = - 44 \div 2 \: + - (i \sqrt{784}) \div 2 \\ a = - 22 + - i \sqrt{16} \sqrt{49} \div 2 \\$
$a = - 22 + - 28i \div 2 \\ a = - 22 + - 14i$
not quite sure where to go from these imaginary numbers...
I DON'T THINK A RIGHT TRIANGLE WITH THOSE DIMENSIONS IS POSSIBLE

8 0

3 years ago