Write the equation of the parabola in vertex form.

Combine any like terms in the expression. If there are no like terms, rewrite the expression.

Llana [10]

If the 3’s were exponents then... i got 50r3

how i solved:

39r3 + 11r3 + 45s3 - 5s3 - 40s3

50r3 + 40s3 - 40s3

50r3 + 0

= 50r3

4 0

3 years ago

Which is NOT a true statement?

rusak2 [61]

Answer:

option 4

Step-by-step explanation:

|a| represents Absolute value, it is the distance from zero that a number is on the number line. And we know distance cannot be negative.

So,

$|a| = a$

$|-a| = a\\\\| \frac{-a}{b}| = \frac{a}{b}\\\\|\frac{a}{-b}| = \frac{a}{b}$

6 0

3 years ago

Read 2 more answers

A coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that

mafiozo [28]

Answer:

(a) The significance level of the test is 0.002.

(b) The power of the test is 0.3487.

Step-by-step explanation:

We are given that a coin is thrown independently 10 times to test the hypothesis that the probability of heads is 0.5 versus the alternative that the probability is not 0.5.

The test rejects the null hypothesis if either 0 or 10 heads are observed.

Let p = <u><em>probability of obtaining head.</em></u>

So, Null Hypothesis, $H_0$ : p = 0.5

Alternate Hypothesis, $H_A$ : p $\neq$ 0.5

(a) The significance level of the test which is represented by $\alpha$ is the probability of Type I error.

Type I error states the probability of rejecting the null hypothesis given the fact that the null hypothesis is true.

Here, the probability of rejecting the null hypothesis means we obtain the probability of observing either 0 or 10 heads, that is;

P(Type I error) = $\alpha$

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

Also, the event of obtaining heads when a coin is thrown 10 times can be considered as a binomial experiment.

So, X ~ Binom(n = 10, p = 0.5)

P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true) = $\alpha$

$\binom{10}{0}\times 0.5^{0} \times (1-0.5)^{10-0} +\binom{10}{10}\times 0.5^{10} \times (1-0.5)^{10-10}$ = $\alpha$

$(1\times 1\times 0.5^{10}) +(1 \times 0.5^{10} \times 0.5^{0})$ = $\alpha$

$\alpha$ = 0.0019

So, the significance level of the test is 0.002.

(b) It is stated that the probability of heads is 0.1, and we have to find the power of the test.

Here the Type II error is used which states the probability of accepting the null hypothesis given the fact that the null hypothesis is false.

Also, the power of the test is represented by (1 - $\beta$ ).

So, here, X ~ Binom(n = 10, p = 0.1)

$1-\beta$ = P(X = 0/ $H_0$ is true) + P(X = 10/ $H_0$ is true)

$1-\beta$ = $\binom{10}{0}\times 0.1^{0} \times (1-0.1)^{10-0} +\binom{10}{10}\times 0.1^{10} \times (1-0.1)^{10-10}$

$1-\beta$ = $(1\times 1\times 0.9^{10}) +(1 \times 0.1^{10} \times 0.9^{0})$

$1-\beta$ = 0.3487

Hence, the power of the test is 0.3487.

3 0

3 years ago

A radio station your cars DJs to play two commercials for every 10 songs they play what is the unit rate of songs to commercial

Ira Lisetskai [31]

5 songs per commercial
or
5 songs/commercial

3 0

3 years ago

I need help is it a, b, c, or d

Salsk061 [2.6K]

It’s B
23x+23
Just add

3 0

3 years ago