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Lina20 [59]
3 years ago
6

What is the equation of a line, in point-slope form, that passes through (-8, 1) and has a slope of 5/6?

Mathematics
1 answer:
max2010maxim [7]3 years ago
5 0

Answer:

y-1=\frac{5}{6}(x+8)

Step-by-step explanation:

1. y-y1=m(x-x1) (point slope form)

2. y1 is the y of your given point and x1 is the x of your given point

3. m is the slope

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(SUPER EASY) ILL GIVE BRAINLIEST TOO. <br><br> just answer all the questions you know.
IrinaK [193]

Answer: x,y. 2,7, 1,

Step-by-step explanation:

8 0
3 years ago
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Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

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⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
Could I have the answer to factorise 16a+12b
Tanzania [10]
Factor out the GCF, which is 4.... 4(4a+3b)
6 0
3 years ago
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Divide7/6 by 3 in simple form
KiRa [710]

Answer:

\frac{7}{6} /3 =7/18

Step-by-step explanation:

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8 0
3 years ago
The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27
Naddik [55]
ANSWER
3\pi sq.\: in.

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

R:r=3:1

We can rewrite it as fractions to get,

\frac{R}{r} = \frac{3}{1}

We make R the subject to get,

R = 3r

The area of the bigger circle can be found using the formula,

Area=\pi {r}^{2}

This implies that,

Area=\pi ({3r})^{2}

Area=9\pi {r}^{2}

But it was given in the question that, the area of the bigger circle is 27π.

27\pi=9\pi {r}^{2}

We divide through by 9π to get,

3 = {r}^{2}

This means that,
r = \sqrt{3}

The area of the smaller circle is therefore

= \pi {( \sqrt{3}) }^{2}

= 3\pi
8 0
4 years ago
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