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Nutka1998 [239]
3 years ago
15

Action potentials are conducted more rapidly when transmission is

Biology
1 answer:
vivado [14]3 years ago
8 0
From node to node on a myelinated axon.

hope this helps :)
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xz_007 [3.2K]

Answer:

C

Explanation:

A. is incorrect because the cell displayed is an animal cell not a plant cell, so it cannot photosynthesize. The organelle shown is actually the ER.

B. is incorrect because the structure labelled is the nucleus, not a vacuole. Vacuoles store substances like waste, not DNA.

C. Is correct because the pickle-like organelle is the Mitochondria, also known as the powerhouse of the cell due to cellular respiration taking place there.

D. Is incorrect because the cellular membrane of the animal cell is not rigid like the cell wall of the plant cell, instead it is more semi-permeable.

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The ""preservationist ethic"" is associated with ______________ .
oksian1 [2.3K]

Answer: maintenance the health of the natural world. Through allocation,exploitation and protection

Explanation:

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This article discusses a group of scientists who are studying an ecosystem. What ecosystem are the scientists studying?
Y_Kistochka [10]

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This article discusses a group of scientists who are studying an ecosystem. What ecosystem are the scientists studying? A the Hudson River ecosystem.

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Help me! True or false! Plz know what your doing
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Read 2 more answers
In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2
Alisiya [41]

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

r = \frac{1500 - 750}{1995 - 1985}  = 750/10 = 75

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

         area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

r = \frac{D(1995) - D(1885)}{1995 - 1985}  = \frac{6 pines/ha - 3pines/ha}{10}  = 0.3 pines/ha

So, on average, each year the number of pines per hectare increases by 0.3

7 0
3 years ago
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