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dsp73
3 years ago
10

What is the measure of the sector shaded above?

Mathematics
1 answer:
mestny [16]3 years ago
8 0

\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\pi \theta r^2}{360}~~ \begin{cases} r=&radius\\ \theta =&angle~in\\ &degrees\\ \cline{1-2} r=&6\\ \theta =&87 \end{cases}\implies A=\cfrac{\pi (87)(6)^2}{360}\implies A=\cfrac{87\pi }{10} \\\\\\ A\approx 27.332\implies \stackrel{\textit{rounded up}}{A=27.3}

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Answer:

x=13,y=0

Step-by-step explanation:

We are given a system of equations

{x}^{2}  +  {y}^{2}  = 169 -  - eqn \: 1 \\ 3x + 2y = 39 -  - eqn \: 2

For equation 1,square all terms to reduce it

√x²+√y²=169

x+y=13

Make x the subject as required by the question to use substitution method

x=13-y

Plug x=13-y into eqn 2

3(13-y)+2y=39

39-3y+2y=39

39-y=39

y=39-39=0

Plug y=0 into equation 1

x+0=13

x=0

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