<u>Solution-</u>
The two parabolas are,

By solving the above two equations we calculate where the two parabolas meet,

Given the symmetry, the area bounded by the two parabolas is twice the area bounded by either parabola with the x-axis.
![\therefore Area=2\int_{-c}^{c}y.dx= 2\int_{-c}^{c}(16x^2-c^2).dx\\=2[\frac{16}{3}x^3-c^2x]_{-c}^{ \ c}=2[(\frac{16}{3}c^3-c^3)-(-\frac{16}{3}c^3+c^3)]=2[\frac{32}{3}c^3-2c^3]=2(\frac{26c^3}{3})\\=\frac{52c^3}{3}](https://tex.z-dn.net/?f=%5Ctherefore%20Area%3D2%5Cint_%7B-c%7D%5E%7Bc%7Dy.dx%3D%202%5Cint_%7B-c%7D%5E%7Bc%7D%2816x%5E2-c%5E2%29.dx%5C%5C%3D2%5B%5Cfrac%7B16%7D%7B3%7Dx%5E3-c%5E2x%5D_%7B-c%7D%5E%7B%20%5C%20c%7D%3D2%5B%28%5Cfrac%7B16%7D%7B3%7Dc%5E3-c%5E3%29-%28-%5Cfrac%7B16%7D%7B3%7Dc%5E3%2Bc%5E3%29%5D%3D2%5B%5Cfrac%7B32%7D%7B3%7Dc%5E3-2c%5E3%5D%3D2%28%5Cfrac%7B26c%5E3%7D%7B3%7D%29%5C%5C%3D%5Cfrac%7B52c%5E3%7D%7B3%7D)
![So \frac{52c^3}{3}=\frac{250}{3}\Rightarrow c=\sqrt[3]{\frac{250}{52}}=1.68](https://tex.z-dn.net/?f=So%20%5Cfrac%7B52c%5E3%7D%7B3%7D%3D%5Cfrac%7B250%7D%7B3%7D%5CRightarrow%20c%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B250%7D%7B52%7D%7D%3D1.68)
3d + 4 = 2 + 3d - 1/2
3d + 4 = 1 1/2 + 3d |subtract 3d from both sides
4 = 1 1/2 FALSE
Answer: No solution ( x ∈ ∅ )
Answer:
D.
or 
Step-by-step explanation:
The given equation is:

Divide through by 3;

Add the square of half the coefficient of x to both sides.


The left hand side is now a perfect square:

Take square root



D.
or 
9514 1404 393
Answer:
- 63 mph
- 3 donut holes per kid
- $0.70 per pound
- $2.25 per km
Step-by-step explanation:
In this context, "per" and "for" mean "divided by."
- 630 mi/(10 h) = 63 mi/h
- (24 dh)/(8 kid) = 3 dh/kid
- $3.50/(5 lb) = $0.70 /lb
- $32/(14 2/9 km) = $32/(128/9 km) = $(9/4)/km = $2.25 /km
Could be as simple as adding area together for the total area of a room if that's not what youre looking for add more details