Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).
This problem can be expressed in a ratio:
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F
</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes
Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
Answer:
12.5%
Step-by-step explanation:
% increase = (new value - initial value)/initial value x 100
= (90-80)/80 x 100
=10/80 x 100
= 12.5%
Step-by-step explanation:
62= -3k + 7k + 42 + 4
62 - 42 - 4 = 4k
16 = 4k
4 = k
Answer: 2.5
Step-by-step explanation:
For this problem, we see that 4km is 1/2 of 8km.
So, we will have to find 1/2 of 5km.
1/2 of 5km = 2.5km
Your answer is 2.5km
