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AleksAgata [21]
3 years ago
15

If sin square theta = 0.75, then cos =

Mathematics
1 answer:
sergeinik [125]3 years ago
6 0

Answer:

\cos\theta=\pm0.5

Step-by-step explanation:

Given:

\sin^2\theta=0.75

To find \cos\theta

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

\sin^2\theta+\cos^2\theta =1

Plugging in  \sin^2\theta=0.75 in the above relation.

0.75+\cos^2\theta =1

Subtracting both sides by 0.75.

0.75+\cos^2\theta-0.75 =1-0.75

\cos^2\theta =0.25

Taking square root both sides.

\sqrt{\cos^2\theta} =\sqrt{0.25}

∴ \cos\theta=\pm0.5  (Answer)

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pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​
yanalaym [24]

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

  • x = 8 \sqrt{3}  \times 2

  • x = 16 \sqrt{3}

now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

  • \tan(30)  =  \dfrac{y}{24}

  • \dfrac{1}{ \sqrt{3} }  =  \dfrac{y}{24}

  • y =   \dfrac{24}{ \sqrt{3} }

  • y = 8 \sqrt{3}
6 0
3 years ago
Suppose eight out of every 20 students are absent from school less than five days a year predict how many students would be abse
ASHA 777 [7]

Answer:

Number of student that will absent = 16000

Step-by-step explanation:

Using direct proportion

8:20 = X:40000

X = (40000 x 8) ÷ 20 = 16000

6 0
3 years ago
The average of 16 consecutive positive integers is 30.5. What is the average of the first 8 integers of this set?
GREYUIT [131]

consecutive integers are 1 apart

16 of them can be represented as

x, x+1, x+2, x+3, x+4, x+5, x+6, x+7, x+8, x+9, x+10, x+11, x+12, x+13, x+14, x+15


the average is \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15}{16}=30.5


there might be some trick to get the average of the first 8 integers only

the average of the first 8 integers would be \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7}{8}=?

how can we get \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7}{8}=? from \frac{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15}{16}=30.5


first, let's match the denomenators (make them both 1 for ease)


multiply the first eqution by 8 to get

x+x+1+x+2+x+3+x+4+x+5+x+6+x+7=8?


multiply the 2nd equation by 16 to get

x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


notice that we can try and force the 1st equation into the 2nd equation by adding some numbers



we can already do this:


x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


[x+x+1+x+2+x+3+x+4+x+5+x+6+x+7]+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


[8?]+x+8+x+9+x+10 x+11+x+12+x+13+x+14+x+15=488


we can try to force another 8? into it

[8?]+x+7+1+x+7+2+x+7+3+x+7+4+x+7+5+x+7+6+x+7+7+x+7+8=488

[8?]+(x)+7+(1+x)+7+(2+x)+7+(3+x)+7+(4+x)+7+(5+x)+7+(6+x)+7+(7+x)+7+8=488

[8?]+(x)+7+(x+1)+7+(x+2)+7+(x+3)+7+(x+4)+7+(x+5)+7+(x+6)+7+(x+7)+7+8=488

group

[8?]+[x+x+1+x+2+x+3+x+4+x+5+x+6+x+7]+7+7+7+7+7+7+7+7+8=488

[8?]+[8?]+8(7)+8=488

16?+64=488

minus 64 from both sides

16?=424

divide both sides by 16

?=26.5


the average of the first 8 integers is 26.5


I'm not sure if there is a simpler way to do it or not

8 0
3 years ago
Could someone please help me with this​
kicyunya [14]

Answer: i think it would be D

Step-by-step explanation:

7 0
3 years ago
Which of the following is not a classification of the number given below? -3
Scilla [17]
Hello!

I know for a fact that -3 classifies as an integer and a rational number for sure. So, that leaves us two options, real number, and whole number.

Given this information I think the correct answer is whole number, but it might also be real number. So sorry if I am wrong! : )

I hope this helps!
Please Rate & Thank!
Please mark as Brainliest!

Have a wonderful day! : )
3 0
4 years ago
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