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frosja888 [35]
2 years ago
10

pllllllls I need help right triangle and trigonometry special right triangles find the value of each variable​

Mathematics
1 answer:
yanalaym [24]2 years ago
6 0

\huge {\mathfrak{Answer :  }}

we know,

\boxed{\cos( \theta)  =  \dfrac{base}{hypotenuse}}

so,

  • \cos(30)  =  \dfrac{24}{x}

  • \dfrac{ \sqrt{3} }{2}  =  \dfrac{24}{x}

  • x =  \dfrac{24 \times 2}{ \sqrt{3} }

  • x = 8 \sqrt{3}  \times 2

  • x = 16 \sqrt{3}

now,

\boxed{ \tan( \theta) =  \frac{perpendcular}{base}  }

  • \tan(30)  =  \dfrac{y}{24}

  • \dfrac{1}{ \sqrt{3} }  =  \dfrac{y}{24}

  • y =   \dfrac{24}{ \sqrt{3} }

  • y = 8 \sqrt{3}
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