Answer:
the answer to the question is y=x+2.
Answer:
A. 2^11
Step-by-step explanation:
(They are basically asking what's 2^4 × 2^7, but with more words.)
I usually do each exponent individually:
2^4 is the same as 2 × 2 × 2 × 2 = 16 (or you could have read the text to figure that out)
2^7 is the same as 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128
Then just multiply 128 and 16 to get 2,048, and see which option also gives you 2,048.
BUT, you can also:
(Combine the exponents together to get your answer. Just remember that if it's multiplication you add them, and if it's division you subtract them.)
2^4 × 2^7
4 + 7 = 11
2^11 (This equals 2,048 btw. You don't even have to check all the options to get the answer).
Hope this helps friend :)
The last part I learned from another user, while answering one of your other questions. I personally find this mind blowing, lol.
Answer:
sorry, i haven't understood your question!! how can i tell which statement is false.
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
<h3>How to rewrite in vertex form?</h3>
The equation is given as:
f(x) = x^2 + 12x + 6
Rewrite as:
x^2 + 12x + 6 = 0
Subtract 6 from both sides
x^2 + 12x = -6
Take the coefficient of x
k = 12
Divide by 2
k/2 = 6
Square both sides
(k/2)^2 = 36
Add 36 to both sides of x^2 + 12x = -6
x^2 + 12x + 36= -6 + 36
Evaluate the sum
x^2 + 12x + 36= 30
Express as perfect square
(x + 6)^2 = 30
Subtract 30 from both sides
(x + 6)^2 -30 = 0
So, the equation f(x) = x^2 + 12x + 6 becomes
f(x) = (x + 6)^2 -30
A quadratic equation in vertex form is represented as:
f(x) = a(x - h)^2 + k
Where:
Vertex = (h,k)
By comparison, we have:
(h,k) = (-6,-30)
Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
Read more about quadratic functions at:
brainly.com/question/1214333
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