Answer:
The question is not clearly stated, below is a possible match of the clearly and completely stated question:
Tony is writing a fraction equivalent to 2/7 using the formula 2*m/7*n. Which statement about m and n must be true so that tony fraction has the same value as 2/7
A. M/n has to be greater than 1
B. M/n has to equal 7
C. M/n has to be greater than 2
D. M/n has to equal 1
Answer:
m/n has to equal 1 (D)
Step-by-step explanation:
since the target for the equaivalent fraction is the same as the equivalent fraction (), the value of
must be equal to 1, so that the multiplication will be:
Answer:
And replacing we got:
And then the final term would be:
Step-by-step explanation:
For this case we have the following expression:
And we can use the binomial theorem given by:
And for this case we want to find the fourth term and using the formula we have:
And replacing we got:
And then the final term would be:
Answer:
Between 150 and 450
Step-by-step explanation:
We are going to find the number by resolving a system of linear equations.
First we write the system equations :
Where C : children, S : students and A : adults
The equation represents the ''full attendance''
The second equation :
This equation represents the totaled receipts.
The system :
has the following associated matrix :
By performing elementary matrix operations we find that the matrix is equivalent to
The new system :
Working with the equations :
Our solution vector is :
For example :
If 0 adults attended ⇒ A = 0
This verify the totaled receipts equation :
150($3)+600($5) = $ 3450
A ≥ 0 ⇒ If A = 0 ⇒ C = 150
C = 150 is the minimum children attendance
From the equation :
S ≥0
600 - 2A ≥ 0
600 ≥ 2A
300≥ A
A is restricted to the interval [ 0, 300]
When A = 0 ⇒ C = 150
When A = 300 ⇒C = 150 + A = 150 + 300 = 450
Children ∈ [ 150,450]
With C being an integer number (including 0)
Also S and A are integer numbers (including 0)