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madam [21]
2 years ago
5

Tony is writing a fraction equivalent to 27 using the formula 2×m7×n. Which statement about m and n must be true so that Tony's

fraction has the same value as 27?
Mathematics
1 answer:
Colt1911 [192]2 years ago
6 0

Answer:

The question is not clearly stated, below is a possible match of the clearly and completely stated question:

Tony is writing a fraction equivalent to 2/7 using the formula 2*m/7*n. Which statement about m and n must be true so that tony fraction has the same value as 2/7

A. M/n has to be greater than 1

B. M/n has to equal 7

C. M/n has to be greater than 2

D. M/n has to equal 1

Answer:

m/n has to equal 1 (D)

Step-by-step explanation:

original\ fraction = \frac{2}{7} \\equivalent\ fraaction = \frac{2\ \times\ m}{7\ \times\ n} \\equivalent\ fraction\ = \frac{2}{7} \times\ \frac{m}{n} \\

since the target for the equaivalent fraction is the same as the equivalent fraction (\frac{2}{7}), the value of \frac{m}{n}  must be equal to 1, so that the multiplication will be:

\frac{2}{7}  \times 1 = \frac{2}{7}

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5 0
2 years ago
An isotope of iodine has a mass of 134 amu. How many neutrons does the
Nina [5.8K]

Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

A = Z + N

Where:

Z: is the number of protons

N: is the number of neutrons

For iodine Z= 53, so if A = 134 the number of neutrons is:

N = A - Z = 134 - 53 = 81

Therefore, the correct option is C. The isotope of iodine contains 81 neutrons.

I hope it helps you!

5 0
2 years ago
What is -2(3x+12y-5-17x-16y+4) simplified?
CaHeK987 [17]
28x + 8y + 2 is the simplified version.
7 0
3 years ago
Read 2 more answers
Please Help!!<br><br>Use Euler’s formula to write in exponential form.
LekaFEV [45]

Answer:

C, 4e^{i(7\pi/4)}

Step-by-step explanation:

To remind you, Euler's formula gives a link between trigonometric and exponential functions in a very profound way:

e^{ix}=\cos{x}+i\sin{x}

Given the complex number 2\sqrt{2}-2i\sqrt{2}, we want to try to get it in the same form as the right side of Euler's formula. As things are, though, we're unable to, and the reason for that has to do with the fact that both the sine and cosine functions are bound between the values 1 and -1, and 2√2 and -2√2 both lie outside that range.

One thing we could try would be to factor out a 2 to reduce both of those terms, giving us the expression 2(\sqrt{2}-i\sqrt{2})

Still no good. √2 and -√2 are still greater than 1 and less than -1 respectively, so we'll have to reduce them a little more. With some clever thinking, you could factor out another 2, giving us the expression 4\left(\frac{\sqrt{2}}{2} -i\frac{\sqrt{2}}{2}\right) , and <em>now </em>we have something to work with.

Looking back at Euler's formula e^{ix}=\cos{x}+i\sin{x}, we can map our expression inside the parentheses to the one on the right side of the formula, giving us \cos{x}=\frac{\sqrt2}{2} and \sin{x}=-\frac{\sqrt2}{2}, or equivalently:

\cos^{-1}{\frac{\sqrt2}{2} }=\sin^{-1}-\frac{\sqrt2}{2} =x

At this point, we can look at the unit circle (attached) to see the angle satisfying these two values for sine and cosine is 7π/4, so x=\frac{7\pi}{4}, and we can finally replace our expression in parentheses with its exponential equivalent:

4\left(\frac{\sqrt2}{2}-i\frac{\sqrt2}{2}\right)=4e^{i(7\pi/4)}

Which is c on the multiple choice section.

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3 years ago
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Mamont248 [21]

Answer:

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