Tony is writing a fraction equivalent to 27 using the formula 2×m7×n. Which statement about m and n must be true so that Tony's
1 answer:
Answer:
The question is not clearly stated, below is a possible match of the clearly and completely stated question:
Tony is writing a fraction equivalent to 2/7 using the formula 2*m/7*n. Which statement about m and n must be true so that tony fraction has the same value as 2/7
A. M/n has to be greater than 1
B. M/n has to equal 7
C. M/n has to be greater than 2
D. M/n has to equal 1
Answer:
m/n has to equal 1 (D)
Step-by-step explanation:
since the target for the equaivalent fraction is the same as the equivalent fraction (), the value of
must be equal to 1, so that the multiplication will be:
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Answer:
2.87%
Step-by-step explanation:
We have the following information:
mean (m) = 200
standard deviation (sd) = 50
sample size = n = 40
the probability that their mean is above 21.5 is determined as follows:
P (x> 21.5) = P [(x - m) / (sd / n ^ (1/2))> (21.5 - 200) / (50/40 ^ (1/2))]
P (x> 21.5) = P (z> -22.57)
this value is very strange, therefore I suggest that it is not 21.5 but 215, therefore it would be:
P (x> 215) = P [(x - m) / (sd / n ^ (1/2))> (215 - 200) / (50/40 ^ (1/2))]
P (x> 215) = P (z> 1.897)
P (x> 215) = 1 - P (z <1.897)
We look for this value in the attached table of z and we have to:
P (x> 215) = 1 - 0.9713 (attached table)
P (x> 215) =.0287
Therefore the probability is approximately 2.87%
