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Novosadov [1.4K]
3 years ago
10

How does a triangular prism look

Mathematics
1 answer:
irina1246 [14]3 years ago
6 0

Answer:

its like a 3d rectangle triangle

Step-by-step explanation:

yes

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Tamara says she used the GCF to factor the expression 21x + 56xy as 7(3x + 8xy). Is she correct? Explain.
coldgirl [10]

Answer:

Tamara incorrectly factored the whole expression.

Step-by-step explanation:

Note that

•21x=3·7·x;

•56xy=2·2·2·7·x·y.

Mark in bold all common factors, then GCF(21x,56xy)=7·x=7x.

Thus,

21x+56xy=7x(3+8y).

Hence, Tamara correctly found the GCF of numbers 21 and 56, but incorrectly factored the whole expression.

6 0
3 years ago
What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?
Artemon [7]

Try this solution (analytic method):

1. if new line is parallel to the given one (y=3x+2) it means the new line has a form y=3x+b, where b - number.

2. In order to calculate 'b', it need to substitute the coordinates of point (6;1) into the equation of the new line:

1=3*6+b, ⇒ b=-17.

3. If to make up the equation of the new line:

y=3x-17

Answer: A

8 0
3 years ago
Can someone tell me what to write of how i found the answer please ?!
Vlad [161]

Answer:

108

Step-by-step explanation:

4−22+135−9

=−18+135−9

=117−9

=108

5 0
3 years ago
When 2/3 is added to a certain number, the sum is 3 greater than twice the number. part 1: set up an equation using n to represe
Gennadij [26K]
2/3 + n = 2n + 3 <== ur equation
2/3 - 3 = 2n - n
2/3 - 9/3 = n
-7/3 = n <== ur solution

or
2/3 + n = 2n + 3...multiply everything by common denominator of 3
2 + 3n = 6n + 9
2 - 9 = 6n - 3n
-7 = 3n
-7/3 = n
7 0
3 years ago
The radius of a nitrogen atom is 5.8*10^-11 meters, and the radius of a beryllium atom is 1.12*10^-10 meters. Which atom has a l
Burka [1]
Nitrogen Radius = 5.8 x 10⁻¹¹ m

Beryllium Radius = 1.12 x 10⁻¹⁰ m

Let's find the quotient of N/Be :

(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1

→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.

Conclusion: the radius of Be is almost double than the radius of N
5 0
3 years ago
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