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Mathematics

1 answer:

velikii [3]3 years ago

6 0

$log(y^{3}\sqrt{\frac{(x + 4)^{9}}{z}})$
$log(y^{3}\sqrt{\frac{(x + 4)^{8}(x + 4)}{z}}$
$log(\frac{y^{3}\sqrt{(x + 4)^{8}}\sqrt{(x + 4)}}{\sqrt{z}})$
$log(\frac{y^{3}(x + 4)^{4}\sqrt{(x + 4)}}{\sqrt{z}})$
$log(\frac{y^{3}(x + 4)^{4}\sqrt{z(x + 4)}}{\sqrt{z}\sqrt{z}})$
$log(\frac{y^{3}(x + 4)^{4}\sqrt{z(x) + z(4)}}{\sqrt{z * z}})$
$log(\frac{y^{3}(x + 4)^{4}\sqrt{xz + 4z}}{\sqrt{z^{2}}})$
$log(\frac{y^{3}(x + 4)^{4}\sqrt{xz + 4z}}{z})$
$(log(y^{3}) + log((x + 4)^{4}) + log(\sqrt{xz + 4z})) - log(z)$
$(3log(y) + 4log(x + 4) + \frac{1}{2}log(xz + 4z)) - log(z)$
$3log(y) + 4log(x + 4) + \frac{1}{2}log(xz + 4z) - log(z)$

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Suppose that a particular candidate for public office is in fact favored by 48% of all registered voters in the district. a poll

Nutka1998 [239]

Given that a particular candidate for public office is in fact favored by 48% of all registered voters in the district, thus p = 0.48

If a polling organization will take a random sample of 550 voters, i.e. n= 550.

The approximate probability that p̂ will be greater than 0.5 is given by:

$P(\hat{p}\ \textgreater \ 0.5)=1-P(\hat{p}\leq0.5) \\ \\ =1-P\left(z\leq \frac{0.5-0.48}{\sqrt{ \frac{0.48(1-0.48)}{550} }} \right) \\ \\ =1-P\left(z\leq \frac{0.02}{\sqrt{ \frac{0.2496}{550} }} \right)=1-P\left(z\leq \frac{0.02}{0.0213} \right) \\ \\ =1-P(z\leq0.9388)=1-0.82609=0.1739$

Therefore, the approximate probability that p̂ will be greater than 0.5, causing the polling organization to incorrectly predict the result of the upcoming election is 0.1739.

5 0

4 years ago

88 points for this question

soldi70 [24.7K]

Answer:

x = 113°

Step-by-step explanation:

the sum of the interior angles of a polygon is

sum = 180° (n - 2) ← n is the number of sides

here n = 6 , then

sum = 180° × 4 = 720°

sum the given angles and equate to 720°