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NemiM [27]
3 years ago
6

What is 953 divided by 6

Mathematics
2 answers:
Kitty [74]3 years ago
8 0

Answer

158 with a remainder of 5 ( also expressed as 953/6 OR 158.333333333333)

Step-by-step explanation:

I wasn't sure if you wanted a fraction, so I put two forms of the answer.

Flauer [41]3 years ago
5 0
The answer is 158.8333333333333
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How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Ksivusya [100]

Answer:

Here we are given with the sides of the triangle as 5m, 16m and 5. The sum of the length of the two sides should be greater than the length of the third side. But this inequality fails here. Hence no triangle can be made.

Hope this helped

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4 0
3 years ago
Correct answers only please! I keep losing points...
Vedmedyk [2.9K]

Answer:

A = $ 7,299.92

A = P + I where

P (principal) = $ 6,000.00

I (interest) = $ 1,299.92

Step-by-step explanation:

A = P(1 + r/n)nt

Where:

A = Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

R = Annual Nominal Interest Rate in percent

r = Annual Nominal Interest Rate as a decimal

r = R/100

t = Time Involved in years, 0.5 years is calculated as 6 months, etc.

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7 0
3 years ago
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choli [55]
It should be the second one
4 0
3 years ago
Need help fast do not understand this one. Solve: (x+5) / (x+8)=1+(6) / (x+1) showing all work.
umka21 [38]

Answer: x=-\frac{17}{3}

Step-by-step explanation:

Given the equation \frac{(x+5)}{(x+8)}=1+\frac{6}{(x+1)}, you need to make the addtition indicated on the right side of the equation:

\frac{(x+5)}{(x+8)}=\frac{(x+1)+6}{(x+1)}\\\\\frac{(x+5)}{(x+8)}=\frac{(x+7)}{(x+1)}

Now, multiply both sides of the equation by (x+8) and (x+1):

(x+1)(x+8)\frac{(x+5)}{(x+8)}=\frac{(x+7)}{(x+1)}(x+1)(x+8)\\\\(x+1)(x+5)=(x+7)(x+8)

Now, apply Distributive property:

x^2+5x+x+5=x^2+8x+7x+56

Simplifying, you get:

6x+5=15x+56

Subtract 5 and 15x from both sides:

6x+5-15x-5=15x+56-15x-5\\\\-9x=51

Finally, divide both sidesby -9:

\frac{-9x}{-9}=\frac{51}{-9}\\\\x=-\frac{17}{3}

5 0
4 years ago
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