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Deffense [45]
3 years ago
11

Which one is greater??

Mathematics
1 answer:
Andrew [12]3 years ago
8 0
224.9>224.92 hope it helps
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Two​ trains, Train A and Train​ B, weigh a total of 489 tons. Train A is heavier than Train B. The difference of their weights i
makvit [3.9K]

Answer:

Weight of Train A = 454 tons

Weight of Train B = 35 tons

Step-by-step explanation:

It is given that:

Let,

A represent weight of Train A

B represent weight of Train B

According to given information:

A + B = 489      Eqn 1

A - B = 419       Eqn 2

Adding Eqn 1 and 2

A + B + A - B = 489 + 419

2A = 908

Dividing both sides by 2

\frac{2A}{2}=\frac{908}{2}\\A = 454

Putting A = 454 in Eqn 1

454 + B = 489

B = 489 - 454

B = 35

Therefore,

Weight of Train A = 454 tons

Weight of Train B = 35 tons

5 0
2 years ago
Who good at angles ?
Kamila [148]

Answer:

JRQ = 56

Step-by-step explanation:

SRQ - SRJ = JRQ

166 - 110 = 56

6 0
3 years ago
Tell me please I need help with this one guys pleaseee thanks you so much :()))
siniylev [52]
A. At the very end
B.one more away from that
C.on the left
7 0
3 years ago
Ayuda es para hoy
vichka [17]

Answer:

1,166 frascos

Step-by-step explanation:

4500 -2456=2044

2044 - 1678=366

366 + 800= 1166

6 0
2 years ago
Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin
Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

time=\frac{distance}{speed}

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

x - 3 = \frac{distance}{80} \\distance = 80(x-3)   - - - - - (2)

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

50(3+x)=80(x-3)

150 +50x=80x-240\\

Next, collecting like terms:

150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\

dividing both sides by 3:

x =  390÷30 = 13

∴ x = 13 minutes

7 0
3 years ago
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