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iris [78.8K]
3 years ago
12

18 = -4x -9 + 3 resolver

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer:

Hope it helps! Mark as brainlist.

wolverine [178]3 years ago
3 0

Answer:

The answer is X=-4 hope this helps.

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Can anyone help me with this?
MAXImum [283]

Answer:

Option A

Step-by-step explanation:

I found it using a calculator online. Its called Desmos Graphing Calculator. Hopefully it can help in the future!

6 0
3 years ago
Two stabilizing wires extend from the top of a pole to the ground, forming right triangles on
FrozenT [24]

Answer: the height of the pole is 16.1 m.

Step-by-step explanation:

The scenario is illustrated in the attached photo.

x represents the height of the pole.

y represents the distance from the foot of one stabilizing wire to the foot of the pole.

30 - y represents the distance from the foot of the other stabilizing wire to the foot of the pole.

In solving the triangles, we would apply the tangent trigonometric ratio which is expressed as

Tan θ, = opposite side/adjacent side.

Considering triangle ACD,

Tan 60 = x/y

x = ytan60 = y × 1.732

x = 1.732y- - - - - - - - -1

Considering triangle BCD,

Tan 38 = x/(30 - y)

x = (30 - y)tan38 = 0.781(30 - y)

x = 23.43 - 0.781y- - - - - - - - -2

Substituting equation 1 into equation 2, it becomes

1.732y = 23.43 - 0.781y

1.732y + 0.781y = 23.43

2.513y = 23.43

y = 23.43/2.513

y = 9.3

x = 1.732y = 1.732 × 9.3

x = 16.1 m

6 0
4 years ago
Select the correct answer.
Llana [10]

Answer:

\huge\boxed{x=2\ and\ y=-3}

Step-by-step explanation:

22(x+yi)+(28+4i)=72-62i\\\\22x+22yi+28+4i=72-62i\\\\(22x+28)+(22y+4)i=72-62i\Rightarrow22x+28=72\ \wedge\ 22y+4=-62\\\\22x+28=72\qquad|\text{subtract 28 from both sides}\\22x=44\qquad|\text{divide both sides by 22}\\\boxed{x=2}\\\\22y+4=-62\qquad|\text{subtract 4 from both sides}\\22y=-66\qquad|\text{divide both sides by 22}\\\boxed{y=-3}

8 0
3 years ago
Simplify the expression:
olga55 [171]

Answer:

The correct answer is 20x-1

5 0
3 years ago
Write the digit in the ten thousands place
mars1129 [50]
For now I don't know the answer to this problem of yours.
8 0
3 years ago
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