Question

WILL MARK BRAINLIEST IF CORRECT❤️❤️ Simplify the expression -5+i/2i Step by step

Answer 1

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2

Step-by-step explanation:

PLZ MARK ME BRAINLYIST

Answer 2

Answer:

For complex numbers,

a + bi and a - bi

they have the interesting property that if you add them you get the real number 2a

and if you multiply them , because of the difference of square pattern, you get a^2 - b^2 i^2

But since i^2 = -1, we end up with a real number as a product.

e.g. 6 - 5i and 6 + 5i are conjugates of each other

sum = 6-5i + 6+5i = 12

product = 36 - 25i^2

= 36 -(-25) = 61

Your question is even easier, since the denominator is a monomial instead of a binomial, so we just have to multiply by i/i

Also I believe, according to the answer, that you have a typo, and you meant

(-5+i)/(2i)

= (-5+i)/(2i) *i/i

= (-5i + i^2)/2i^2)

= (-5i +i^2)/-2

= (-5i - 1)/-2

= (1 + 5i)/2 or they way they have it: 1/2 + 5i/2