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katovenus [111]
3 years ago
5

The length of a pencil is measured with two rulers. Report the length of the pencil from each ruler with the proper number of di

gits.

Mathematics
1 answer:
Roman55 [17]3 years ago
6 0

Answer

Length measured using Ruler A= 1.17 dm

Length measured using Ruler B=1.18 dm

Step by Step Explanation:

I have added the missing photograph which shows the length of pencil being measured with two rulers.

Ruler A has marking separated by 1 dm

Ruler B has marking separated by 0.1 dm

Length measured using Ruler A= 1.17 dm

(As we can see I have added the middle markers, we can see the tip of pencil is somewhere between 1 and 1.25, it is more than 1.125 but lesser than 1.25, it is somewhere around 1.2 and 1.125 dm, approximately equal to one half of 1.25 which is 1.125 with addition of one of the three halves of half of 1.125 which is 1.125+0.045 dm hence 1.17dm)

Length measured using Ruler B=1.18 dm

(we can see the tip of pencil is just before 1.2 dm, it is clear that the value is precisely 1.18 and not 1.19 dm)

<u><em>Tip:Always measure one more decimal than given by the ruler when unsure about the exact value</em></u>

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Take the value of x-4, and make it positive, then subtract three.  The graph would look like the following.



5 0
4 years ago
ou find a deck of cards and know that the deck has too many clubs and spades in it. The deck has 59 cards. If you were to draw t
sashaice [31]
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

\dfrac{\binom{13}1\binom{13+c}1}{\binom{59}2}=\dfrac{13(13+c)}{1711}

but this would imply that c=-4, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".

Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

\dfrac{\binom{13}1}{\binom{59}1}\cdot\dfrac{\binom{13+c}1}{\binom{58}1}=\dfrac{13(13+c)}{3422}

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7 0
3 years ago
The perimeter of a rectangular garden is 110ft. The length is 5 ft greater than the width. Find the length and width.
tigry1 [53]

P = perimeter

L = length

W = width

Formula for the perimeter of a rectangle = L + L + W + W  or  P = 2L + 2W

You know:

P = 110ft

L = W + 5  [length is 5ft greater than the width]

So plug this into the formula:

P = 2L + 2W             Substitute/plug in (W + 5) for L

110 = 2(W + 5) + 2W           Distribute/multiply 2 into (W + 5)

110 = (2)W + (2)5 + 2W

110 = 2W + 10 + 2W       Combine like terms (2W + 2W)

110 = 4W + 10       Subtract 10 on both sides

110 - 10 = 4W + 10 - 10

100 = 4W     Divide 4 on both sides to get "W" by itself

\frac{100}{4}=\frac{4W}{4}

25 = W        Now that you know the width, plug it into the equation for length

L = W + 5       Plug in 25 for W

L = 25 + 5

L = 30

L = 30 ft

W = 25 ft

PROOF

P = 2L + 2W

110 = 2(30) + 2(25)

110 = 60 + 50

110 = 110

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