Answer:
% GENOTYPE
FF = 0%
Ff = 50%
ff = 50%
% PHENOTYPE
Black fur = 50%
Grey fur = 60%
Explanation:
This question involves a single gene coding for fur color in dogs. The allele for grey fur (F) is dominant over the allele for black fur (f). This means that a heterozygous dog (Ff) will have a grey fur.
In this question, a heterozygous female (Ff) is said to cross with a recessive male (ff) i.e. Ff × ff. The following gametes will be produced by each parent:
Ff - F and f
ff - f and f
Using these gametes in a punnet square (see attached image), the following genotypic proportion of offsprings will be produced:
Ff - 1/2 = 50%
ff - 1/2 = 50%
Ff is phenotypically GREY while ff is phenotypically BLACK. This means that 50% of the offsprings will be black and 50% will be grey.
