y = x^2 + 2x...eqn 1
y = 3x + 20...eqn 2
subst for y in eqn 1...
=> x^2 +2x = 3x +20
=> x^2 - x - 20 =0
=> (x-5) (x+4) =0
=> x = 5 or -4
for x =5, y = 35 (sub for x in eqn 1 or 2)
for x = -4, y = 8 (sub for x in eqn 1 or 2)
Answer:
24
Step-by-step explanation:
This is the same question as before just flipped around
The answer would be B C E hope this helps :)
<h2><em>hope</em><em> it</em><em> helps</em></h2>
Answer:
The answer of this question is (D) 8
