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2 years ago

H divide 4 = 9 I need help with this

Mathematics

1 answer:

Makovka662 [10]2 years ago

6 0

Yo yo what’s your name on the phone back on your internet please send it

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HELP ME PLEASE IVE BEEN STRUGGLING WITH THIS FOR SO LONG

Ber [7]

Answer:

Step-by-step explanation:

Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

= [360-(m∠CBA+m∠CDE)]/2

= [360 - 180]/2

= 90

finally,

m∠ACE= 180 - (m∠BCA + m∠DCE)

= 180 - 90

= 90

8 0

1 year ago

A rental car company offers a rental package for a mid-size car.

skelet666 [1.2K]

Answer:

$y=45x+40$

Step-by-step explanation:

Let

x -----> the number of days

y ----> the total cost in dollars,

we know that

The equation of a linear function in slope intercept form is equal to

$y=mx+b$

where

m is the slope o rate of the linear equation

b is the y-coordinate of the y-intercept

Remember that the y-intercept is the value of y when the value of x is equal to zero

In this problem we have

The slope is equal to the rental cost per day

$m=45\frac{\$}{day}$

When the number of days is equal to zero (x=0) the total cost is equal to $40 (administrative fee for the cleaning and maintenance of the car)

The y-intercept is the point (0,40)

$b=\$40$

substitute the values

$y=45x+40$

8 0

3 years ago

I need help in a and b

Deffense [45]

A.24cm
B. 246.12 I'm is the answer!!!!!

3 0

2 years ago

2(4 – 16) – (–30) 2(–12) – (–30) 24 – (–30) 54

VLD [36.1K]

Step-by-step explanation:

2(4 – 16) – (–30) 2(–12) – (–30) 24 – (–30) 54= 2×4-2×16 -×-30×2×-12-×-30×24-×-30= 8-32+30-24+30×24+30: 732

3 0

3 years ago

Read 2 more answers

How would I find the integral of <img src="https://tex.z-dn.net/?f=%5Cint%5Cfrac%7Btdt%7D%7Bt%5E4%2B2%7D" id="TexFormula1" title

kotegsom [21]

Let $t=\sqrt y$ , so that $t^2=y$ , $t^4=y^2$ , and $\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}$ . Then

$\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}$

Now let $y=\sqrt2\tan z$ , so that $\mathrm dy=\sqrt2\sec^2z\,\mathrm dz$ . Then

$\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C$

Transform back to $y$ to get

$\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C$

and again to get back a result in terms of $t$ .

$\dfrac1{2\sqrt2}\arctan\left(\dfrac{t^2}{\sqrt2}\right)+C$

3 0

3 years ago

H divide 4 = 9 I need help with this​

H divide 4 = 9 I need help with this