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nasty-shy [4]
3 years ago
14

Determine the equation of the graph and select the correct answer (-4,-1)

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
4 0

Answer:

(-4,-1)

Step-by-step explanation:

Assuming the graph is the one shown in the attachment.

The forward sloping line has a slope of 1 and a y-intercept of 3.

The equation of this line is y=x+3

The horizontal line has a slope of 0 and y-intercept of -1.

It's equation is y=-1

The two lines intersect at (-4,-1)

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In ΔUVW, the measure of ∠W=90°, UW = 60, VU = 61, and WV = 11. What is the value of the sine of ∠U to the nearest hundredth?
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Where on a number line are the numbers x for which <br><br>|x|&gt;1
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Answer:

Step-by-step explanation:

Given the inequality

|x|> 1

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Find the measurements (the length L and the width W) of an inscribed rectangle under the line with the 1st quadrant of the x &am
Leni [432]

The question is incomplete. Here is the complete question.

Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -\frac{3}{4}x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.

Answer: L = 1; W = 9/4; A = 2.25;

Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:

A = x.y

A = x(-\frac{3}{4}.x + 3)

A = -\frac{3}{4}.x^{2}  + 3x

To maximize, we have to differentiate the equation:

\frac{dA}{dx} = \frac{d}{dx}(-\frac{3}{4}.x^{2}  + 3x)

\frac{dA}{dx} = -3x + 3

The critical point is:

\frac{dA}{dx} = 0

-3x + 3 = 0

x = 1

Substituing:

y = -\frac{3}{4}x + 3

y = -\frac{3}{4}.1 + 3

y = 9/4

So, the measurements are x = L = 1 and y = W = 9/4

The maximum area is:

A = 1 . 9/4

A = 9/4

A = 2.25

6 0
3 years ago
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