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Eva8 [605]
3 years ago
9

How can you determine the amount of work done on an object? (joules, work, power...etc.)

Physics
1 answer:
Novay_Z [31]3 years ago
7 0
Work done is equal to force by distance; so you take the force exerted, in newtons, and multiply that by the direction it's moved (from the starting point in a line, not along the path it's taken.)
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The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge
lesya [120]

Answer:

Loss, \Delta E=-10.63\ J

Explanation:

Given that,

Mass of particle 1, m_1=m =0.66\ kg

Mass of particle 2, m_2=7.4m =4.884\ kg

Speed of particle 1, v_1=2v_o=2\times 6=12\ m/s

Speed of particle 2, v_2=v_o=6\ m/s

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

m_1v_1+m_2v_2=(m_1+m_2)V

V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}

V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}

V = 6.71 m/s

Initial kinetic energy before the collision,

K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)

K_i=135.43\ J

Final kinetic energy after the collision,

K_f=\dfrac{1}{2}(m_1+m_2)V^2

K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2

K_f=124.80\ J

Lost in kinetic energy,

\Delta K=K_f-K_i

\Delta K=124.80-135.43

\Delta E=-10.63\ J

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

7 0
3 years ago
The brightness of a star depends on its (color, composition of atmosphere, or distance from earth), and stars that are closer lo
PolarNik [594]

Answer:

Distance, Brighter

Explanation:

Think of a flash light, one close and one far which is brighter and which is dimmer.  

Hope this is what your teacher put as the answer!

5 0
3 years ago
Read 2 more answers
An enzyme works best at 98.6°f. the equation used to describe it requires the temperature to be in k. what is the correct tempe
Marina86 [1]

310.093k.

Given,

Best temperature for enzymes to work = 98.6°F

Unknown :

We need to convert the temperature from fahrenheit to kelvin.

Writing down the equation to be used in the problem's solution correctly:

K = (F x 0.55) + 255.37

F = (K - 255.37) x 1.8

The temperatures are expressed in kelvin (K) and fahrenheit (F), respectively.

There first equation would be significantly more quicker to use :

K = (98.6 x 0.555) + 255.37

= 54.723 + 255.37

= 310.093K

➤ The activity and rate of an enzyme reaction typically increase with temperature, while a decrease in temperature slows the enzymatic reaction. Each enzyme's activity peaks at its individual optimum temperature, and it decreases above and below that point.

Find more on enzymes at : brainly.com/question/1596855

#SPJ4

5 0
1 year ago
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow
Oksana_A [137]

Answer:

a)\omega=1.36rad/s

b)\omega=12.99rpm

c)F=705.6N

Explanation:

a) The angular velocity is related to the centripetal acceleration by the formula a_{cp}=\omega^2r, which for our purposes we will write as:

\omega=\sqrt{\frac{a_{cp}}{r}}

Since <em>we want this acceleration to be 1.5 times that due to gravity</em>, for our values we will have:

\omega=\sqrt{\frac{1.5g}{r}}=\sqrt{\frac{(1.5)(9.8m/s^2)}{(8m)}}=1.36rad/s

b) 1 rpm (revolution per minute) is equivalent to an angle of 2\pi radians in 60 seconds:

1\ rpm=\frac{2\pi rad}{60s} =\frac{\pi}{30}rad/s

Which means <em>we can use the conversion factor</em>:

\frac{1\ rpm}{\frac{\pi}{30}rad/s}=1

So we have (multiplying by the conversion factor, which is 1, not affecting anything but transforming our units):

\omega=1.36rad/s=1.36rad/s(\frac{1\ rpm}{\frac{\pi}{30}rad/s})=12.99rpm

c) The centripetal force will be given by Newton's 2nd Law F=ma, so on the centripetal direction for our values we have:

F=ma=(48kg)(1.5)(9.8m/s^2)=705.6N

8 0
3 years ago
You shine a flashlight on a pond. The light hits the pond at an angle of 70° to the normal of the pond. What is angle between th
Solnce55 [7]

Answer:

(d)  44.8°

Explanation:

For refraction,  

Using Snell's law as:

\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}

Where,  

Θ₁ is the angle of incidence  

Θ₂ is the angle of refraction

n₁ is the refractive index of air which is 1

n₂ is the refractive index of water which is 4/3

Given that angle of incidence = 70°

So,  

\frac {sin\theta_2}{sin70}=\frac {1}{\frac {4}{3}}

{sin\theta_2}=0.7048

<u>Angle of refraction = sin⁻¹ 0.7048 = 44.8°.</u>

7 0
4 years ago
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