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Eva8 [605]
2 years ago
9

How can you determine the amount of work done on an object? (joules, work, power...etc.)

Physics
1 answer:
Novay_Z [31]2 years ago
7 0
Work done is equal to force by distance; so you take the force exerted, in newtons, and multiply that by the direction it's moved (from the starting point in a line, not along the path it's taken.)
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Polyunsaturated fatty acids which is Omega-3 fatty acids.
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The format specifier ________ is a placeholder for an int value. %d %n %int %s
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%d is a format specifier that is a placeholder for an int value. It tells the compiler that we want to print an integer value that is present in variable a. In this way there are several format specifiers in c.

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Provide the following information for each of the three types of radiations from naturally radioactive materials. Be sure to inc
scoundrel [369]

<em>Alpha radiation:</em>  Particles.  Each alpha particle is a little bundle of 2 protons and 2 neutrons ... identical to the nucleus of a Helium atom.

Charge  . . . +2 elementary charges

Mass  . . . 4 Atomic Mass Units

Relative penetrating power  . . . low

The effect an electric field would have on it . . . Since the alpha particle has a positive charge, it's repelled by other positive charges, and attracted toward negative charges.

<em>Beta radiation</em>:  Particles.  Each beta particle is an electron.

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Mass  . . . 0.00055 AMU

Relative penetrating power  . . . medium

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<em>Gamma radiation</em>:  electromagnetic wave, verrrrry short wave, high frequency

Charge . . . electromagnetic wave, no charge

Mass  . . . electromagnetic wave, no mass

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5 0
3 years ago
When balancing an equation, you can
attashe74 [19]
D. write down the coefficients
7 0
3 years ago
awhite billiard ball with mass mw = 1.47 kg is moving directly to the right with a speed of v = 3.01 m/s and collides elasticall
pochemuha

Answer:

speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

initial kinetic energy = final kinetic energy

KE = 6.66 J

Explanation:

Since there is no external force on the system of two balls so here total momentum of two balls initially must be equal to the total momentum of two balls after collision

So we will have

momentum conservation along x direction

m_1v_{1i} + m_2v_{2i} = m_1v_{1x} + m_2v_{2x}

now plug in all values in it

1.47 \times 3.01 + 0 = 1.47 v_1cos68 + 1.47 v_2cos22

so we have

3.01 = 0.375v_1 + 0.927v_2

similarly in Y direction we have

m_1v_{1i} + m_2v_{2i} = m_1v_{1y} + m_2v_{2y}

now plug in all values in it

0 + 0 = 1.47 v_1sin68 - 1.47 v_2sin22

so we have

0 = 0.927v_1 - 0.375v_2

v_2 = 2.47 v_1

now from 1st equation we have

3.01 = 0.375 v_1 + 0.927(2.47 v_1)

v_1 = 1.13 m/s

v_2 = 2.78 m/s

so speed of white ball is 1.13 m/s and speed of black ball is 2.78 m/s

Also we know that since this is an elastic collision so here kinetic energy is always conserved to

initial kinetic energy = final kinetic energy

KE = \frac{1}{2}(1.47)(3.01^2)

KE = 6.66 J

5 0
3 years ago
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