Answer:
92 protons, 146 neutrons
Explanation:
Uranium will always have the same amount of protons, because that is what defines the element. Uranium has 92 protons, meaning that the rest of the mass of the atom comes from neutrons. 238-92=146 neutrons. Hope this helps!
Answer:
Explanation:
We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .
∫ E ds = q / ε
Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so
∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .
This also represents total flux coming out of the charge q on all sides .
This is equal to q / ε where ε is a constant called permittivity which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .
If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .
It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors
1 ) charge q and
2 ) the permittivity of medium ε around .
Answer: Scanning Tunneling Microscope
Explanation:
The answer is, of course, the greatest Star Trek fan art imaginable: images literally built out of individual atoms. The images are the work of IBM scientists who created the unique artwork with a two-ton machine called the Scanning Tunneling Microscope that moves single atoms across a tiny piece of copper.
Based on internet sources, <span>the basic formulas are: v^2/r = (at)^2/r = a ==> at^2 = r ==> t = sqrt(r/a).
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<span>Assuming the missing units are mutually compatible, as in the following example, they don't need to be known. </span>
<span>Acceleration = 1.6 cramwells/s^2 </span>
<span>Radius = 150 cramwells </span>
<span>t = sqrt(150/1.6) = 9.68 s.
I hope this helps.</span>
That's "displacement". It only depends on the beginning and ending locations, and doesn't care about the route between them.
