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2 years ago

What is the answer to this question 3x+1=10

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

6 0

Step-by-step explanation:

$3x+1=10 \\ \\ \therefore \: 3x = 10 - 1 \\ \\ \therefore \: 3x = 9 \\ \\ \therefore \: x = \frac{9}{3} \\ \\ \: \: \: \: \: \: \: \: \huge \purple { \boxed{\therefore \: x = 3}} \\ \\$

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On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be

Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

The distance from Saugerties to Catskill would be 3 inches on this map.

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is 1 inch = 2.5 miles.

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

y = 3 inches.

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0

3 years ago

Can someone please help me with this problem? I tried inputting the numbers into the standard deviation equation but I did not g

Juliette [100K]

Answer:

97.8

Step-by-step explanation:

add together 97.3 +0.5

6 0

2 years ago

HELP! PLEASEE I’ve been stuck!! I WILL GIVE BRAINLY,,, THANK YOU SM

faltersainse [42]

The theoretical answer for the following question provided above would be found if you study

3 0

2 years ago

Read 2 more answers

You decide to buy some berries as a surprise for your aunt from the local farmer’s market. However, when you arrive, you see tha

wariber [46]

There are 4 possibilities of a right choice. Your Aunt has 1 favorite. So you probability would be 1/4 or .25
Hope This Helps and God Bless!

3 0

3 years ago

Read 2 more answers

A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica

umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be more than that.

X is a random variable of Poisson distribution with mean $\mu = 3$ , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) = 0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is expected to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0

3 years ago