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Over [174]
3 years ago
7

Question 13. thank You so much

Mathematics
1 answer:
Cloud [144]3 years ago
4 0
First thing we need is the volume of the fish tank. We simply multiply the three dimensions to get

V = L*W*H
V = 2.5*1*1.5
V = 3.75

The fish tank can hold 3.75 cubic feet of water if its completely full

-------------------------

We are told that "one cubic foot of water weighs about 62.4 pounds". 

So we have this ratio
1 cubic foot of water: 62.4 pounds

Multiply both sides of that ratio by 3.75 which was the volume of the fishtank

1 cubic foot of water: 62.4 pounds
3.75*1 cubic foot of water: 3.75*62.4 pounds
3.75 cubic feet of water: 234 pounds

The fishtank can hold 234 pounds of water

note: this is assuming that the walls are strong enough to withstand the pressure/weight of water without cracking or breaking

Answer: 234 pounds

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The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.4 minutes and a standard deviation of 3.5
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Answer:

0.6672 is the required probability.            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.4 minutes

Standard Deviation, σ = 3.5 minutes

We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.

According to central limit theorem the sum measurement of n is normal with mean \mu and standard deviation \sigma\sqrt{n}

Sample size, n = 37

Standard Deviation =

=\sigma\times \sqrt{n} = 3.5\times \sqrt{37}=21.28

P(taxi and takeoff time will be less than 320 minutes)

P( \sum x < 320) = P( z < \displaystyle\frac{320 - 37(8.4)}{21.28}) = P(z < 0.4323)

Calculation the value from standard normal z table, we have,  

P(\sum x < 320) =0.6672 = 66.72\%

0.6672 is the probability  that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

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3 years ago
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