Let x=the smallest integer, x+1=the second smallest, x+2=the greatest.
x+x+1+x+2=141
3x+3=141
3x=138
x=46
46 is the smallest integer
The solution to the problem is as follows:
<span>√28 = √(4 * 7) = √4 * √7 = 2√7.
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<span>√64 = 8
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Therefore, √28 + √64 = <span>2√7. + 8
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