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inna [77]
3 years ago
5

...............................

Mathematics
2 answers:
stepladder [879]3 years ago
5 0

Answer:

............................... is not a school related question

NeTakaya3 years ago
3 0
...................points :p
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Im kinda confused on this. i need help.​
RideAnS [48]

<u>Given </u><u>:</u><u>-</u>

  • A graph is given to us .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The equation in slope intercept form .

<u>Answer</u><u> </u><u>:</u><u>-</u>

From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,

\sf\longrightarrow y intercept = 5 .

\sf\longrightarrow slope = 5/2 .

Now here we can use the slope intercept form as ,

\sf\longrightarrow y = mx + c

\sf\longrightarrow y = 5/2x + 5

<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>y </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>5</u><u>.</u>

4 0
2 years ago
Read 2 more answers
What is y equals negative three fourths plus two equal
Crazy boy [7]
Y = -3/4 + 2

y = 1 1/4


7 0
3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
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Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &2&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &3&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
Bob and Caitlyn are playing a trading-card game. Between them, they have 81 cards. Bob has 7 fewer cards than Caitlyn.
Alina [70]
We know that Bob and Caitlyn are playing a trading-card game. Between them, they have 81 cards. <span>Bob has 7 fewer cards than Caitlyn. Since Bob has 7 cards fewer them Caitlyn we have to divide by 2 and subtract 7. 

81 / 2 = 40 [rounded] 

40 - 7 = cards Bob has 

= 33 cards bob has 


</span>
3 0
3 years ago
Read 2 more answers
That's the answer... I don't understand how you get -43a and -6
Roman55 [17]
You want the explanation. Or answer?
4 0
3 years ago
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