Question :
There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each. There are also 4 different meats. She buys One-half of a pound of each. How much total meat and cheese did Yasuko buy at the deli? a) One-fourth pounds
b) 2 and one-fourth pounds
c) 4 and one-fourth pounds
d) 4 and one-half pounds
Answer:
c) 4 and one-fourth pounds
Step-by-step explanation:
From the question:
There are 3 different cheeses at the deli. Yasuko buys Three-fourths of a pound of each.
Total pounds of cheese = 3 × (3/4)
= 9/4 pounds of cheese
There are also 4 different meats. She buys One-half of a pound of each.
Total pounds of meats she bought = 4 × (1/2)
= 4/2 pounds of meat
The total pounds of total meat and cheese did Yasuko bought at the deli =
= 9/4 pounds of cheese + 4/2 pounds of meat
L.C.M = 4
= 9 × 1 + 4 × 2/4
= 9 + 8/4
= 17/4
= 4 1/4 pounds
In words is 4 and one-fourth pounds
The line should equal 180 degrees, so we would subtract 122 from 180 to get 58 degrees. Since the triangle is equilateral, each angle is the same measure, so I believe m<1 should be 58 degrees.
Given:
Two electrons are added to each of six atoms in a group.
To find:
The expression for the net change in charge.
Solution:
Charge of atoms = Number protons - Number of electrons.
Let number of atoms be x.
6 atoms = 2 electrons added
1 atom = 
electrons added
1 atom = 
electrons added
x atoms = 
electrons added
Therefore, the net change in charge is represented by the expression 
because we subtract number of electrons to find atom charge, where, x is the number of atoms.
6 atoms = 2 protons removed
1 atom = protons removed
1 atom = protons removed
x atoms = protons removed
Therefore, the net change in charge is represented by the expression , where, x is the number of atoms.
<span>The diagonals are congruent.
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