Answer:
The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = an elementary or secondary school teacher from a city is a female
<em>Y</em> = an elementary or secondary school teacher holds a second job
The information provided is:
P (X) = 0.66
P (Y) = 0.46
P (X ∩ Y) = 0.22
The addition rule of probability is:
Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:
Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Answer:
The degrees of freedom are given by;
The significance level is 0.1 so then the critical value would be given by:
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:
The statsitic would be given by:
Where O represent the observed values and E the expected values
The degrees of freedom are given by;
The significance level is 0.1 so then the critical value would be given by:
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
-10 and 8 multiply them to equal 80 but if there both negative it will be a positive 80 because if you multiply 2 negatives its postive hope this helps
