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maks197457 [2]
2 years ago
15

These marbles are placed in a bag and two of them are randomly drawn what is the probability of drawing two yellow marbles if th

e first one is not placed back into the bag before the second draw

Mathematics
2 answers:
Galina-37 [17]2 years ago
8 0

Answer:

1/90

Step-by-step explanation:

1/10 x 1/9 = 1/90

Sliva [168]2 years ago
7 0

Answer:

It is 1/45

Step-by-step explanation:

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Ayyyyyyyy help me even if u can only help with 1 answer it wud be appreciated
Lisa [10]

Answer:

7. 225, 315

Step-by-step explanation:

4 0
2 years ago
Help plssssss!!!!!!!
In-s [12.5K]
For the first question asking about the slope 3/4 and y intercept -2 would be (y=0.75x-2) because 3/4=0.75 and the y intercept -2 is b and you’re just placing it into the formula y=Mx+b m=slope b=y intercept.
7 0
3 years ago
The volume of this regular pentagonal pyramid is 82.5 cubic meters. What is the height of the pyramid?
a_sh-v [17]

the height of the pentagonal pyramid is 5. 70 meters

<h3>Volume of a regular pentagonal pyramid</h3>

The formula for determining the volume of a regular pentagonal pyramid is given as;

V=5/12tan(54°)ha^2

Where

  • a is the base edge
  • h is the height

We have the volume to be;

volume = 82. 5 cubic centers

height = h

a = 5m

Substitute the values

82. 5 = \frac{5}{12} × tan 54 × h ×5^2

82. 5 = 0. 42 × 1. 3764 × 25 × h

Make 'h' subject of formula

h = \frac{82. 5}{14. 45}

h = 5. 70 meters

The height of the pentagonal pyramid is 5. 70 meters

Thus, the height of the pentagonal pyramid is 5. 70 meters

Learn more about a pentagonal pyramid here:

brainly.com/question/16315924

#SPJ1

6 0
11 months ago
Find a101 of the sequence 5,8,11,
guajiro [1.7K]

Answer:

305

Step-by-step explanation:

This sequence es the sum of 3

5+3 =8

8+3 = 11

then

101 = 100 + 1

the fisrt date is 5

the another 100:

100*3 = 300

300 + 5 = 305

3 0
3 years ago
What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?
natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are:  (-2,-1) and (1,0)</em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of \triangle BCD are:   B(-3,1), C(3,3) and D(-1,-3)

Now, the endpoints of the mid-segment of \triangle BCD which is parallel to BC will be the mid-points of sides BD and CD.

<u>Formula for the coordinate of mid-point</u> :   (\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}), where (x_{1}, y_{1}) and (x_{2}, y_{2}) are two endpoints.

So, the mid-point of BD will be:  (\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)

and the mid-point of CD will be:  (\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)

Thus, the endpoint coordinates for the mid-segment of \triangle BCD that is parallel to BC are  (-2,-1) and (1,0)

4 0
3 years ago
Read 2 more answers
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